It is SnO2
Why? Because:
Tin has a charge of 4 and Oxygen has a charge of 2. Their charges are switched to make a compound; therefore, the chemical formula would be written as Sn2O4. Then, you have to simplify that so it would be written as SnO2.
There are two such tin oxides: Tin (II) oxide with formula SnO and tin (IV) dioxide, with formula SnO2.
Nitrogen dioxide NO2 Nitrogen(IV) oxide
tin (IV) oxide it is actually Sn2O4 in simplified form.
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
The chemical formula for Tin(IV) hydroxide is Sn(OH)4.
The chemical formula for tin(IV) oxide is SnO2. Tin(III) oxide doesn't exist.
The chemical formula for tin(IV) oxide is SnO2. Tin(III) oxide doesn't exist.
The chemical formula for tin reacting with oxygen is SnO2, which is known as tin(IV) oxide or stannic oxide.
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
There are two such tin oxides: Tin (II) oxide with formula SnO and tin (IV) dioxide, with formula SnO2.
That is the chemical formula. SnCl4 is the chemical formula for tin(IV) chloride.
The chemical formula of tin IV acetate is Sn(C2H3O2)4.
Nitrogen dioxide NO2 Nitrogen(IV) oxide
SnS2 is the chemical formula of tin(IV) sulfide or tin disulfide.
The Answer To Your Question Is.... tin (IV) oxide
The formula for the tin four ion is Sn+4