The chemical symbol (not formula) of chlorine is Cl.
The state of sulfur is solid at 298 K. Sulfur's symbol is S and its atomic number is 16.
The chemical formula for the compound formed between rubidium and sulfur is Rb2S. Rubidium is in Group 1 of the periodic table with a +1 oxidation state, while sulfur is in Group 16 with a -2 oxidation state, so they combine in a 1:1 ratio to form Rb2S.
Work this out like this Chroium you are told is oxidation state +3. Selenium is in group 16 along with oxygen and sulfur so it will have a preferred oxidation state of -2. Then balance it, oxidation staes can be treated like ionic charges:- Cr2Se3
sulfur sodium chloride sand is a homogeneous mixture (solution)
Formula: BrN Br in 3+ oxidation state
The chemical symbol (not formula) of mercury is Hg.
The chemical symbol for lead in its standard state is Pb.
The chemical symbol of zinc is Zn.
The chemical formula for sulfur oxide is SOx, where x can vary depending on the oxidation state of sulfur in the compound. One common example is sulfur dioxide (SO2), which is formed when sulfur is burned in the presence of oxygen.
The compound formed from aluminum and sulfur is aluminum sulfide, which has the chemical formula Al2S3. In this compound, aluminum has a +3 oxidation state, while sulfur has a -2 oxidation state.
The state of sulfur is solid at 298 K. Sulfur's symbol is S and its atomic number is 16.
The formula for sulfur oxide can vary based on the oxidation state of sulfur. For example, sulfur dioxide is represented by the formula SO2, while sulfur trioxide is represented by SO3.
Assuming the standard 2 oxidation state, Pb(NO3)2
The chemical name for the compound with the formula Na2S is sodium sulfide. In this compound, sodium (Na) is in the +1 oxidation state, and sulfur (S) is in the -2 oxidation state. The subscript "2" in the formula indicates that there are two sodium atoms for every one sulfur atom in the compound.
The chemical formula for gold(I) sulfide is Au2S. In this compound, gold has a +1 oxidation state, denoted by the Roman numeral I, and sulfur has a -2 oxidation state. The formula indicates that two gold atoms combine with one sulfur atom to form the compound. The correct name for this compound is gold(I) sulfide.
The chemical formula for the compound formed between rubidium and sulfur is Rb2S. Rubidium is in Group 1 of the periodic table with a +1 oxidation state, while sulfur is in Group 16 with a -2 oxidation state, so they combine in a 1:1 ratio to form Rb2S.
Work this out like this Chroium you are told is oxidation state +3. Selenium is in group 16 along with oxygen and sulfur so it will have a preferred oxidation state of -2. Then balance it, oxidation staes can be treated like ionic charges:- Cr2Se3