Chromium(III)Sulfite
The compound formed between F- and Cr2+ ions is written as CrF2. The compound has a 2:1 ratio of fluoride ions (F-) to chromium ions (Cr2+).
Cr2CrO43 is not a correct chemical formula. If you meant Cr2(CrO4)3, it would indicate a compound with two chromium atoms and three chromate ions. Chromate ions have a charge of -2 each, so the compound would have a charge of 6- in total.
The chemical reaction between Cr2O3 and SO3 forms chromium sulfate (Cr2(SO4)3).
Potassium dichromate reacts with nitric acid to form chromium(III) nitrate, nitrogen dioxide gas, and water. The balanced chemical equation for this reaction is: 3K2Cr2O7 + 8HNO3 → 3Cr(NO3)3 + 3KNO3 + 4H2O + 3NO2.
Chromium III is Cr3+. The roman numeral tells you the charge. Sulfide is S2-. You can figure this out from the periodic table. Sulfur needs two electrons to be like Argon, the next noble gas. When they form a compound, they combine in a ratio such that the total positive charge balances the total negative charge. 2 Cr3+ ions have a total charge of +6. 3 S2- ions have a total charge of -6. So the formula is Cr2S3.
Cr2(SO4)3 Chromium sulphate.
The compound name for K2Cr2O7 is potassium dichromate.
The chemical formula for the cation in the compound Cr(CO3)2 is Cr2 and for the anion is CO32-.
The compound formed between F- and Cr2+ ions is written as CrF2. The compound has a 2:1 ratio of fluoride ions (F-) to chromium ions (Cr2+).
The chemical formula for chromium (III) sulfate is Cr2(SO4)3.
The name for Cr2 is chromium(II) and the name for NO2 is nitrogen dioxide.
Cr2(SO3)3
The chemical formula of chromic sulfite is Cr2(SO3)3.
Chromium(III) Sulphate is Cr2(SO4)3 . Chromium(II) Sulphate (much rarer) is CrSO4
Chromium(III) borate has the chemical formula CrBO3.
The chemical formula for chromic bisulfate is Cr(HSO4)3. This compound is formed when chromium sulfate (Cr2(SO4)3) reacts with sulfuric acid (H2SO4), resulting in the replacement of some sulfate ions by bisulfate ions (HSO4-). The compound is a coordination complex where the chromium ion is surrounded by bisulfate ligands in a specific geometric arrangement.
(NH4)2 Cr2 O7 --------> N2 + 4H2O + Cr2 O3