Fluorine's atomic number is 9. Thus, neutral fluorine has 9 protons and 9 electrons. It's total configuration then is 1s2 2s2 2p5, so its valence configuration is 2s2 2p5.
The electron configuration for a fluorine ion (F-) is 1s2 2s2 2p6, which is equivalent to the neon noble gas electron configuration. This is because the fluorine ion gains one electron to achieve a stable octet configuration similar to a noble gas.
When fluorine forms an ionic bond to achieve the electron configuration of neon, it gains one electron to become a fluoride anion. By gaining an electron, fluorine's outer electron shell is filled with eight electrons, similar to neon's stable electron configuration. This allows the fluorine atom to achieve greater stability.
No it has 9, I only know this from studying chemistry at school and from textbooks.
The element that will have a noble gas configuration after donating one electron to fluorine is lithium. By donating one electron, lithium achieves the electron configuration of helium, which is a noble gas.
Yes, potassium and fluorine form an ionic bond. Potassium readily donates one electron to fluorine, which then gains a stable electron configuration by accepting this electron to form potassium fluoride.
The condensed electron configuration for copper is Ar 3d10 4s1.
Fluorine's electron configuration is 1s2 2s2 2p5, and since fluoride is just fluorine with an extra electron, or F-1, its electron configuration is 1s2 2s2 2p6.
The electron configuration of mendelevium is [Rn]5f13.7s2.
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The condensed electron configuration for polonium is [Xe] 6s2 4f14 5d10 6p4
1s2,2s2,2p5
[Kr],5s2,4d10,5p1
The "Noble gas electron configuration," or the condensed electron configuration, for F is [He] 2s2 3p5.
The short form electron configuration for fluorine is [He] 2s2 2p5. The [He] represents the electron configuration of helium, which has 2 electrons in its outer shell.
The element with the electron configuration He2s2 2p5 is fluorine. The atomic number of fluorine is 9, which means it has 9 electrons. The electron configuration represents 2 electrons in the 2s orbital and 5 electrons in the 2p orbital, giving a total of 7 valence electrons.
The electron configuration for an atom of fluorine is [He]2s2.2p5.
The electron configuration of fluorine is 1s2 2s2 2p5.