Problem: Calculate the density of CH4 gas at STP.
How to solve the problem: Density is mass over volume. (D = M/V), this is what we need to find.
Information you will need:
Molecular weight of CH4 = 16.05 g/mol
STP = Pressure (P) = 1 atm (unit of pressure) and Temperature (T) à 273 K (unit of temperature)
Use the ideal gas law. PV = nRT
n = mass/ mw (molecular weight- "The molecular weight is essentially the same thing as the molar mass except that, as the name implies, it refers to molecules rather than just elements. The molar mass and molecular weight is typically given in units of grams per mole." - Answers.com)
n = unit of mass
V = unit of volume
PV = (mass/mw) RT
Steps:
Re-arrange the ideal gas law equation, so that you get M/V (which is density).
Mass/V = mw (molecular weight) x P/ RT
Mass/V = (16.05 g/mol) x 1 atm / [0.08206 (L)(atm)/ (mol)(K)] (273 degrees K)
Because of the gas law constant, atm (unit of pressure), K (unit of temperature) and mol (numerical unit) cancel out, and we are left with units of grams per L (unit of volume), which is what we want. Thus, our answer will be in units of g/L.
Plug the equation into your scientific calculator.
I got 7.16 x 10^-1 g/L
At standard temperature and pressure (STP), the gas that occupies the highest volume is hydrogen.
The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, 0.75 mol of methane gas would occupy 16.8 liters (0.75 mol x 22.4 L/mol = 16.8 L).
1 mole of gas at STP (standard temperature and pressure) occupies 22.4 liters of volume. This is known as the molar volume of a gas at STP. Additionally, the gas has a pressure of 1 atmosphere and a temperature of 273 K at STP.
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 5.6 liters of methane is equal to 5.6/22.4 = 0.25 moles of methane.
The volume of 0.0100 mol of CH4 gas at STP (Standard Temperature and Pressure) is 224 mL. This is based on the ideal gas law and the molar volume of a gas at STP, which is 22.4 L/mol. Converting this to milliliters gives 224,000 mL/mol.
This volume is 79,79 litres.
At standard temperature and pressure (STP), the gas that occupies the highest volume is hydrogen.
The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, 0.75 mol of methane gas would occupy 16.8 liters (0.75 mol x 22.4 L/mol = 16.8 L).
1 mole of gas at STP (standard temperature and pressure) occupies 22.4 liters of volume. This is known as the molar volume of a gas at STP. Additionally, the gas has a pressure of 1 atmosphere and a temperature of 273 K at STP.
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 5.6 liters of methane is equal to 5.6/22.4 = 0.25 moles of methane.
At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. This is known as the molar volume of a gas at STP.
0.25 moles
At STP (standard temperature and pressure), one mole of any gas occupies 22.4 liters. This means that 144 liters of methane gas contain 144/22.4 moles of CH4. Using the molar mass of CH4 (16 g/mol), you can calculate the mass of methane gas in grams.
1 mol of any gas has a volume of 22.4 L at STP
1 mole of gas at STP occupies 22.4 liters.
The volume of 0.0100 mol of CH4 gas at STP (Standard Temperature and Pressure) is 224 mL. This is based on the ideal gas law and the molar volume of a gas at STP, which is 22.4 L/mol. Converting this to milliliters gives 224,000 mL/mol.
The volume of a mole of any gas at Standard Temperature and Pressure (STP) is approximately 22.4 liters. This is known as the molar volume of a gas at STP and is a standard value used in gas calculations.