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Problem: Calculate the density of CH4 gas at STP.
How to solve the problem: Density is mass over volume. (D = M/V), this is what we need to find.
Information you will need:
Molecular weight of CH4 = 16.05 g/mol
STP = Pressure (P) = 1 atm (unit of pressure) and Temperature (T) à 273 K (unit of temperature)
Use the ideal gas law. PV = nRT
n = mass/ mw (molecular weight- "The molecular weight is essentially the same thing as the molar mass except that, as the name implies, it refers to molecules rather than just elements. The molar mass and molecular weight is typically given in units of grams per mole." - Answers.com)
n = unit of mass
V = unit of volume
PV = (mass/mw) RT
Steps:
Re-arrange the ideal gas law equation, so that you get M/V (which is density).
Mass/V = mw (molecular weight) x P/ RT
Mass/V = (16.05 g/mol) x 1 atm / [0.08206 (L)(atm)/ (mol)(K)] (273 degrees K)
Because of the gas law constant, atm (unit of pressure), K (unit of temperature) and mol (numerical unit) cancel out, and we are left with units of grams per L (unit of volume), which is what we want. Thus, our answer will be in units of g/L.
Plug the equation into your scientific calculator.
I got 7.16 x 10^-1 g/L
What else can I help you with?
Which gas occupies the highest volume at STP?
At standard temperature and pressure (STP), the gas that occupies the highest volume is hydrogen.
What is the volume in liters of 0.75 mol of methane gas (CH4)?
The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, 0.75 mol of methane gas would occupy 16.8 liters (0.75 mol x 22.4 L/mol = 16.8 L).
What is the characteristic of 1 mole of gas at stp?
1 mole of gas at STP (standard temperature and pressure) occupies 22.4 liters of volume. This is known as the molar volume of a gas at STP. Additionally, the gas has a pressure of 1 atmosphere and a temperature of 273 K at STP.
How many moles of methane CH4 are present in 5.6L of the gas at STP?
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 5.6 liters of methane is equal to 5.6/22.4 = 0.25 moles of methane.
What volume is occupied by 55 g of methane CH4 (g) at STP?
The easiest way to approach this is to remember molar volume: one mole of every (ideal) gas will occupy 22.4 liters at STP - a gas occupies 22.4 L/mol. Since we know that, we can set up a simple proportion that follows the thought process: if one mole of a gas occupies 22.4 liters (at STP), then 2.88 grams of methane occupies x liters. But before we do that, we have a problem: the measurement given is in the wrong units - it is in grams when molar volume is in moles. Therefore, we first need to convert 2.88 grams of methane to moles. To do this, we need the molar mass of the compound - the sum of all the atomic masses involved. Carbon = 12.0 grams Hydrogen = 1.01 grams × 4 atoms = 4.04 grams ------------------------------------------------------------- Methane = 16.04 grams To convert grams to moles: Grams of substance ÷ Molar mass (in grams) = Moles of substance 2.88 grams CH4 ÷ 16.04 grams CH4 = 0.180 moles CH4 Now we follow through with our proportion: 22.4 L/1 mol = x L/.180 mol x = 4.03 L 2.88 grams of methane occupies 4.03 liters at STP
What volume will 3.56 moles of methane occupy at STP?
This volume is 79,79 litres.
How many moles of methane gas occupy 32 L at STP?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters. To find the number of moles of methane gas in 32 liters, you can use the formula: moles = volume (L) / volume per mole (L/mole). Thus, the calculation is 32 L / 22.4 L/mole = approximately 1.43 moles of methane gas.
Which gas occupies the highest volume at STP?
At standard temperature and pressure (STP), the gas that occupies the highest volume is hydrogen.
What is the volume in liters of 0.75 mol of methane gas (CH4)?
The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, 0.75 mol of methane gas would occupy 16.8 liters (0.75 mol x 22.4 L/mol = 16.8 L).
What is the characteristic of 1 mole of gas at stp?
1 mole of gas at STP (standard temperature and pressure) occupies 22.4 liters of volume. This is known as the molar volume of a gas at STP. Additionally, the gas has a pressure of 1 atmosphere and a temperature of 273 K at STP.
How many moles of methane CH4 are present in 5.6L of the gas at STP?
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 5.6 liters of methane is equal to 5.6/22.4 = 0.25 moles of methane.
How many grams of methane gas CH4 are contained in a volume of 144 liters at STP?
At STP (standard temperature and pressure), one mole of any gas occupies 22.4 liters. This means that 144 liters of methane gas contain 144/22.4 moles of CH4. Using the molar mass of CH4 (16 g/mol), you can calculate the mass of methane gas in grams.
What does a molar volume of a gas at STP occupy?
At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. This is known as the molar volume of a gas at STP.
How many moles of methane are presentin 5.6L of the gas at stp?
0.25 moles
What does avagadros law say about a gas at STP?
1 mol of any gas has a volume of 22.4 L at STP
What volume is occupied by 55 g of methane CH4 (g) at STP?
The easiest way to approach this is to remember molar volume: one mole of every (ideal) gas will occupy 22.4 liters at STP - a gas occupies 22.4 L/mol. Since we know that, we can set up a simple proportion that follows the thought process: if one mole of a gas occupies 22.4 liters (at STP), then 2.88 grams of methane occupies x liters. But before we do that, we have a problem: the measurement given is in the wrong units - it is in grams when molar volume is in moles. Therefore, we first need to convert 2.88 grams of methane to moles. To do this, we need the molar mass of the compound - the sum of all the atomic masses involved. Carbon = 12.0 grams Hydrogen = 1.01 grams × 4 atoms = 4.04 grams ------------------------------------------------------------- Methane = 16.04 grams To convert grams to moles: Grams of substance ÷ Molar mass (in grams) = Moles of substance 2.88 grams CH4 ÷ 16.04 grams CH4 = 0.180 moles CH4 Now we follow through with our proportion: 22.4 L/1 mol = x L/.180 mol x = 4.03 L 2.88 grams of methane occupies 4.03 liters at STP
What is the volume in milliliters of 0.0100 mol of ch4 gas at stp?
The volume of 0.0100 mol of CH4 gas at STP (Standard Temperature and Pressure) is 224 mL. This is based on the ideal gas law and the molar volume of a gas at STP, which is 22.4 L/mol. Converting this to milliliters gives 224,000 mL/mol.
