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At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters. To find the number of moles of methane gas in 32 liters, you can use the formula: moles = volume (L) / volume per mole (L/mole). Thus, the calculation is 32 L / 22.4 L/mole = approximately 1.43 moles of methane gas.
What else can I help you with?
What volume will 3.56 moles of methane occupy at STP?
This volume is 79,79 litres.
How many moles of methane are presentin 5.6L of the gas at stp?
0.25 moles
How many moles of of hydrogen gas occupy 112L at stp?
Ideal gas equation. PV = nRT ===============
What volume does 0.685 moles of gas occupy at stp?
The volume is approx. 15,35 litres.
Description of 16.0 grams of methane?
16.0 grams of methane (CH4) is equivalent to about 0.92 moles of methane, since the molar mass of methane is approximately 16.04 g/mol. In terms of molecules, this would be approximately 5.53 x 10^22 molecules of methane.
What volume will 3.56 moles of methane occupy at STP?
This volume is 79,79 litres.
How many moles of methane are presentin 5.6L of the gas at stp?
0.25 moles
How many moles of methane CH4 are present in 5.6L of the gas at STP?
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 5.6 liters of methane is equal to 5.6/22.4 = 0.25 moles of methane.
How many moles of of hydrogen gas occupy 112L at stp?
Ideal gas equation. PV = nRT ===============
What volume does 0.685 moles of gas occupy at stp?
The volume is approx. 15,35 litres.
Description of 16.0 grams of methane?
16.0 grams of methane (CH4) is equivalent to about 0.92 moles of methane, since the molar mass of methane is approximately 16.04 g/mol. In terms of molecules, this would be approximately 5.53 x 10^22 molecules of methane.
How many liters of oxygen are needed to exactly react with 27.8 g of methane at STP?
1) First find the number of moles of methane in 27.8 g using the molar mass.See the Related Question to the left of this answer "How do you convert from grams to moles and also from moles to grams?" to do that.2) Then write the balanced reaction. Methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). See the related question "How do you balance a chemical reaction?" to do that.3) That will tell you the ratio of moles of methane to moles of oxygen (it will be 2 to 1). So from Part 1, multiply the number of moles of methane by 2 to get moles of oxygen. Then, use the Ideal Gas Law to find out how many liters that will take up at STP. Use the Related Question link "How do you solve Ideal Gas Law problems?" to do that.
What volume does 0.50 mole of NH3 at STP occupy?
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
At stp how many moles of helium would occupy 1.00l?
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
How many molecules are in 30 liters of methane (CH4) at STP?
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. So, in 30 liters of methane, there would be 30/22.4 = 1.3393 moles. One mole of methane contains 6.022 x 10^23 molecules, therefore 30 liters of methane at STP would contain 1.3393 * 6.022 x 10^23 = 8.07 x 10^23 molecules.
How do you calculate the number of liters of 3.30 moles of helium at stp?
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
What volume occupied by 1.50 moles of CH4 at STP is?
The amount of oxygen is 0,067 moles.
