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What volume does 0685 mol of gas occupy at stp?
At standard temperature and pressure (STP), one mole of an ideal gas occupies 22.4 liters. Therefore, to find the volume occupied by 0.685 mol of gas at STP, you can multiply the number of moles by the volume per mole: 0.685 mol × 22.4 L/mol = 15.34 liters. Thus, 0.685 mol of gas occupies approximately 15.34 liters at STP.
How many moles of methane gas occupy 32 L at STP?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters. To find the number of moles of methane gas in 32 liters, you can use the formula: moles = volume (L) / volume per mole (L/mole). Thus, the calculation is 32 L / 22.4 L/mole = approximately 1.43 moles of methane gas.
What is the volume 0.323 mol sample of gas will occupy at 265k and pressure of 0.900atm?
Using the ideal gas law, V = (nRT)/P, where V is volume, n is moles, R is the gas constant, T is temperature in Kelvin, and P is pressure, we can calculate the volume to be 7.34 L.
What happens to the volume of a gas when the number of moles doubles?
If the number of moles of a gas doubles at constant pressure and temperature, the volume of the gas will also double according to Avogadro's law. This is because the volume of a gas is directly proportional to the number of moles present.
How many moles of oxygen are there in a thirty six centimeter cube of the gas at room temperature and pressure?
What you need to know to work this out is that:- Moles of gases at standard temperature pressure (With P and T constant) are proportional to the volume they occupy, divided by their specific gas constant.
What volume does 34.53 moles of a gas occupy?
Approx. 774 litres.
What volume does 0685 mol of gas occupy at stp?
At standard temperature and pressure (STP), one mole of an ideal gas occupies 22.4 liters. Therefore, to find the volume occupied by 0.685 mol of gas at STP, you can multiply the number of moles by the volume per mole: 0.685 mol × 22.4 L/mol = 15.34 liters. Thus, 0.685 mol of gas occupies approximately 15.34 liters at STP.
What volume is occupied of 2.4 moles of chlorine?
The volume that 2.4 moles of chlorine gas would occupy depends on the temperature and pressure of the gas, according to the ideal gas law (PV = nRT). At standard temperature and pressure (STP), which is 0°C and 1 atm pressure, 2.4 moles of chlorine gas would occupy approximately 53.75 liters.
What is the volume of 0.8 moles of chlorine gas at Standard Temperature and Pressure?
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
What is the volume of 3.5mol of CO2 gas at STP?
The volume of gas that 3.5 moles of oxygen occupy can be easily found using the relationship of PV=nRT where P is the pressure, V is the volume, n is the moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
What volume will 0.405 g of krypton gas occupy at STP?
First we need the moles of krypton gas. Monoatomic gas.0.405 grams Kr (1 mole Kr/83.80 grams)= 0.004833 moles krypton gas======================Now the ideal gas equation.PV = nRT(1 atm)(X volume) = (0.004833 moles Kr)(0.08206 L*atm/mol*K)(298.15 K)= 0.118 Liters of krypton gas--------------------------------------
How many moles of methane gas occupy 32 L at STP?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters. To find the number of moles of methane gas in 32 liters, you can use the formula: moles = volume (L) / volume per mole (L/mole). Thus, the calculation is 32 L / 22.4 L/mole = approximately 1.43 moles of methane gas.
What volume would be occupied by 2 moles of propane gas C3H8 at standard conditions?
1 mole of any gas at STP occupies 22.4 liters. Thus, 2 moles propane will occupy 2 x 22.4 L = 44.8 liters.
What is the volume 0.323 mol sample of gas will occupy at 265k and pressure of 0.900atm?
Using the ideal gas law, V = (nRT)/P, where V is volume, n is moles, R is the gas constant, T is temperature in Kelvin, and P is pressure, we can calculate the volume to be 7.34 L.
What happens to the volume of a gas when the number of moles doubles?
If the number of moles of a gas doubles at constant pressure and temperature, the volume of the gas will also double according to Avogadro's law. This is because the volume of a gas is directly proportional to the number of moles present.
If the number of moles of gas decrease what happens to the volume?
If the number of moles of gas decreases, the volume of the gas will decrease as well, assuming constant temperature and pressure. This is described by Boyle's Law, which states that the volume of a gas is inversely proportional to the number of moles of gas when pressure and temperature are held constant.
What volume will 2.00 moles of hydrogen gas occupy at 2.62 ATM of pressure and 300.C?
Using the ideal gas law, V = (nRT)/(P), where n = moles, R = gas constant, T = temperature in Kelvin, and P = pressure in atm. Plug in the values to find the volume: V = (2.00 moles * 0.0821 L.atm/mol.K * 300 K) / (2.62 atm) = 49.22 L. Therefore, 2.00 moles of hydrogen gas at 2.62 ATM and 300.C will occupy 49.22 liters of volume.
