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First we need the moles of krypton gas. Monoatomic gas.
0.405 grams Kr (1 mole Kr/83.80 grams)
= 0.004833 moles krypton gas
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Now the ideal gas equation.
PV = nRT
(1 atm)(X volume) = (0.004833 moles Kr)(0.08206 L*atm/mol*K)(298.15 K)
= 0.118 Liters of krypton gas
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∙ 12y ago
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What volume will 0.416 g of krypton gas occupy at Stp?
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stupid question
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