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How many milliliters of Cl2 gas must you have to obtain 0.30g at STP in chemistry?

You can use the ideal gas law to solve this problem. First, convert 0.30 g of Cl2 to moles. Then use the molar volume of gas at STP (22.4 L/mol) to determine the volume of Cl2 gas needed. Convert this volume to milliliters (1 L = 1000 mL) to find the answer.


What volume will 3.56 moles of methane occupy at STP?

This volume is 79,79 litres.


What volume (in liters) does 2.895 mole of oxygen occupy at STP?

The volume is 64,8 L.


What volume will 15 g of NH3 occupy at stp?

The volume of ammonia is 19,5 L.


What volume does 0.685 moles of gas occupy at stp?

The volume is approx. 15,35 litres.


what volume in milliliters will 0.00922 g of H2 gas occupy at STP?

0.00922 g of H2 gas will occupy approximately 0.100 L at STP


At stp condtions 11g of SO2 have a volume of?

At STP conditions, 11g of SO2 will occupy a volume of approximately 5.6 liters.


What volume does 1 mole of gas particles occupy at stp?

1 mole of gas particles at STP (Standard Temperature and Pressure) occupies a volume of 22.4 liters.


What is the density of Cl2 gas at STP?

what is the volume of a balloon containing 50.0 moles of O2 gas at a pressure of 15.0 atm at 28 degrees


A chemical reaction produces 0.884 mol of H2S gas What volume will that gas occupy at STP?

The volume is 22,1 L.


What does a molar volume of a gas at STP occupy?

At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. This is known as the molar volume of a gas at STP.


What is the volume of 1.9 moles of chlorine gas (Cl2) at standard temperature and pressure (STP) 12 L 22.4 L 43 L 81 L?

At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. Therefore, the volume of 1.9 moles of chlorine gas (Cl2) can be calculated as follows: 1.9 moles × 22.4 L/mole = 42.56 L. Rounding to the nearest option, the volume of 1.9 moles of Cl2 at STP is approximately 43 L.