volume is 3.85 cubic dm. or litre.....
.75
1 mole of gas occupies 22.4 liters at STP. Therefore 3.5/22.4 = 0.15625 moles of SO2. There are thus 0.15625 moles of O2 needed to react with solid sulfur because S + O2 ---->SO2. 0.15625 moles of oxygen occupies 0.15625 x 22.4 liters = 3.5 liters O2 required.
Density: BF3 = 0.00276 g/cm3 (anhydrous gas)Volume: 0.155 (g) / 0.00276 (g/cm3) = 56.16 = 56.2 cm3 (gas volume at STP)
54 liters at STP (standard temperature and pressure)
8.10 L
.75
Approx. 112 mL.
SO2 molecular weight = 64. 576/64 = 9 so 576g = 9 moles. 1 mole of gas occupies 22.4 liters at STP. So 9 x 22.4 = 201.6 liters.
2.24 L O2 (= 0.100 mol O2) is needed to react with 0.200 moles of SO2 to form SO3
1.12 X10 to the 23rd power molecules SO2
The volume of 10.9 mol of helium at STP is 50 litres.
1 mole of gas occupies 22.4 liters at STP. Therefore 3.5/22.4 = 0.15625 moles of SO2. There are thus 0.15625 moles of O2 needed to react with solid sulfur because S + O2 ---->SO2. 0.15625 moles of oxygen occupies 0.15625 x 22.4 liters = 3.5 liters O2 required.
24.5
The amount of oxygen is 0,067 moles.
Most commonly, this refers to the volume of a gas at Standard conditions of Temperature and Pressure (often abbreviated, STP). This standard allows accurate comparisons of volumes. The volume of a gas (any gas) at STP is 22.4 liters per mole.
1 mole SO2 weights 32+2*16 = 64 gram S + 2*O and it's volume is 22.4 l You can do with that to calculate density (g/L) ?
This volume is 65,68 L.