0
What else can I help you with?
What is the volume of 72 grams of SO2?
To find the volume of 72 grams of SO2, you need to convert the mass to moles using the molar mass of SO2 (64.06 g/mol). Then, you can use the ideal gas law to calculate the volume at a given temperature and pressure.
What is the total number of liters of SO3 produced when 32 liters of SO2 reacts completely?
If 32 liters of SO2 react completely, they will produce an equal volume of SO3, because the reaction is balanced. Therefore, the total number of liters of SO3 produced will also be 32 liters.
What will be the volume of 16.0 grams of sulfur dioxide gas at 35 C and 97 ATM?
T = 35 degrees celsius = 308.15 degrees KelvinP = 97 atmV = ?n = 16.0 g SO2 / 64.06 g SO2 = 0.250 mol SO2
How many grams of sulfur must be burned to give 100.0 g of SO2?
To calculate the number of grams of sulfur burned to produce 100.0 g of SO2, we first need to find the molar mass of SO2. The molar mass of SO2 is 64.1 g/mol. Since there is one sulfur atom in each molecule of SO2, the molar mass of sulfur is 32.1 g/mol. Therefore, 32.1 grams of sulfur must be burned to produce 100.0 g of SO2.
How many moles are present in 128 grams of sulphur dioxide?
To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.
What is the volume of 72 grams of SO2?
To find the volume of 72 grams of SO2, you need to convert the mass to moles using the molar mass of SO2 (64.06 g/mol). Then, you can use the ideal gas law to calculate the volume at a given temperature and pressure.
At stp condtions 11g of SO2 have a volume of?
At STP conditions, 11g of SO2 will occupy a volume of approximately 5.6 liters.
What is the volume of 11 g of SO2 at STP conditions?
At STP conditions (standard temperature and pressure), the volume occupied by 1 mole of ideal gas is 22.4 liters. Since the molar mass of SO2 is approximately 64 g/mol, 11 g of SO2 is about 0.172 moles. Therefore, the volume of 11 g of SO2 at STP would be approximately 3.85 liters.
What is the total number of liters of SO3 produced when 32 liters of SO2 reacts completely?
If 32 liters of SO2 react completely, they will produce an equal volume of SO3, because the reaction is balanced. Therefore, the total number of liters of SO3 produced will also be 32 liters.
What is the volume of 72.0 grams of sulfur dioxide?
To find the volume of a gas such as sulfur dioxide with a given mass, you need to know the temperature, pressure, and molar mass. Assuming standard temperature and pressure conditions (STP), the volume of 72.0 grams of sulfur dioxide can be calculated using the ideal gas law equation (PV = nRT), where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.
What will be the volume of 16.0 grams of sulfur dioxide gas at 35 C and 97 ATM?
T = 35 degrees celsius = 308.15 degrees KelvinP = 97 atmV = ?n = 16.0 g SO2 / 64.06 g SO2 = 0.250 mol SO2
What volume of oxygen is needed to react with a solid sulfur to form 3.5L of SO2?
1 mole of gas occupies 22.4 liters at STP. Therefore 3.5/22.4 = 0.15625 moles of SO2. There are thus 0.15625 moles of O2 needed to react with solid sulfur because S + O2 ---->SO2. 0.15625 moles of oxygen occupies 0.15625 x 22.4 liters = 3.5 liters O2 required.
How many moles of SO2 is present in 0.45 grams of sulfur dioxide?
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
How many grams are in 0.400 mole of SO2?
To calculate the number of grams in 0.400 moles of SO2, you first need to determine the molar mass of SO2, which is approximately 64.07 g/mol. Then, you multiply the molar mass by the number of moles: 64.07 g/mol x 0.400 mol = 25.63 grams of SO2.
How many gram-moles in 320 grams of SO2?
To determine the number of gram-moles in 320 grams of SO2, you first need to find the molar mass of SO2, which is 64.07 g/mol. Then you divide the given mass (320 g) by the molar mass to get the number of moles. Therefore, 320 grams of SO2 is equivalent to 5 moles.
What is the volume in liters of SO2 gas needed to completely consume 1.40 kg of H2S if the density of SO2 is 2.279 kg per m3?
Though there is no common reaction known of how to 'consume' (whatever that may be: H2S and SO2 are both very toxic!) hydrogen sulfide, one might deduce the molar reaction ratio of H2S to SO2 from the 1 to 1 atomic sulfur content, this gives us equal amounts in moles H2S and SO2.Since 1.40 kg H2S equals 1.40(kg) / 0.03418(kg/molH2S) = 40.96 mole H2S one can easily calculate that the same amount SO2 weights 40.96(molSO2) * 0.06407(kg/molSO2) = 2.62 kg SO2 which equals 2.62(kgSO2) / 2.279(kg/m3) = 1.15 m3 SO2 gasMolar masses: 0.03418 kg/mol H2S and 0.06407 kg/mol SO2
How many grams are in 0.75 moles of SO2?
To convert moles to grams, you need to use the molar mass of the compound. The molar mass of SO2 is approximately 64.07 g/mol. Multiplying the number of moles by the molar mass gives: 0.75 moles x 64.07 g/mol = 48.0525 grams of SO2.
