The volume of 72 grams of SO2 is 27,4 L.
T = 35 degrees celsius = 308.15 degrees KelvinP = 97 atmV = ?n = 16.0 g SO2 / 64.06 g SO2 = 0.250 mol SO2
To calculate the number of grams of sulfur burned to produce 100.0 g of SO2, we first need to find the molar mass of SO2. The molar mass of SO2 is 64.1 g/mol. Since there is one sulfur atom in each molecule of SO2, the molar mass of sulfur is 32.1 g/mol. Therefore, 32.1 grams of sulfur must be burned to produce 100.0 g of SO2.
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. The molar mass of SO2 is 64 grams/mol. Thus, for 576 grams of SO2, you first need to find the number of moles (576 g / 64 g/mol) and then use the ideal gas law to find the volume: V = (nRT) / P, where n is the number of moles, R is the ideal gas constant, T is the temperature, and P is the pressure.
To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.
The molar mass of C5H12 is 72 grams/mole.
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
At STP conditions, 11g of SO2 will occupy a volume of approximately 5.6 liters.
To calculate the number of grams in 0.400 moles of SO2, you first need to determine the molar mass of SO2, which is approximately 64.07 g/mol. Then, you multiply the molar mass by the number of moles: 64.07 g/mol x 0.400 mol = 25.63 grams of SO2.
To determine the number of gram-moles in 320 grams of SO2, you first need to find the molar mass of SO2, which is 64.07 g/mol. Then you divide the given mass (320 g) by the molar mass to get the number of moles. Therefore, 320 grams of SO2 is equivalent to 5 moles.
To convert moles to grams, you need to use the molar mass of the compound. The molar mass of SO2 is approximately 64.07 g/mol. Multiplying the number of moles by the molar mass gives: 0.75 moles x 64.07 g/mol = 48.0525 grams of SO2.
To find the total mass of 0.75 moles of SO2, you need to calculate the molar mass of SO2 and then multiply it by the number of moles. The molar mass of SO2 is approximately 64.06 g/mol. Therefore, the total mass of 0.75 moles of SO2 is 0.75 mol * 64.06 g/mol = 48.045 grams.
To determine the number of molecules of sulfur dioxide in 72 g of the substance, we first need to calculate the number of moles of sulfur dioxide present. The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol. Therefore, 72 g of sulfur dioxide is equal to 72 g / 64 g/mol = 1.125 moles. Next, we use Avogadro's number, which is 6.022 x 10^23 molecules/mol, to convert moles to molecules. Therefore, there are approximately 6.78 x 10^23 molecules of sulfur dioxide in 72 g of the substance.
T = 35 degrees celsius = 308.15 degrees KelvinP = 97 atmV = ?n = 16.0 g SO2 / 64.06 g SO2 = 0.250 mol SO2
To calculate the number of grams of sulfur burned to produce 100.0 g of SO2, we first need to find the molar mass of SO2. The molar mass of SO2 is 64.1 g/mol. Since there is one sulfur atom in each molecule of SO2, the molar mass of sulfur is 32.1 g/mol. Therefore, 32.1 grams of sulfur must be burned to produce 100.0 g of SO2.
About 0.1587 pounds to 72 grams.
To find the number of grams in 2.65 mol of SO2, you need to multiply the molar mass of SO2 by the number of moles given. The molar mass of SO2 is approximately 64.07 g/mol. So, 2.65 mol of SO2 would be equivalent to 2.65 mol * 64.07 g/mol = 169.48 g.
The molar mass of SO2 is approximately 64.07 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles by the molar mass: 0.75 moles x 64.07 g/mol = 48.05 grams Therefore, the total mass of 0.75 moles of SO2 is 48.05 grams.