2.24 L O2 (= 0.100 mol O2) is needed to react with 0.200 moles of SO2 to form SO3
It takes 2 moles of NO to form 2 moles of NO2, so to form 4.67 moles of NO2 you would need 4.67 moles of NO.
For every 2 moles of A3, 3 moles of B2 react to form 6 moles of AB. Since we have 10 moles of A3, we need to double the moles of B2 reacting, which would be 15 moles of B2 to fully react with the 10 moles of A3. This would produce 30 moles of AB.
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
To determine the volume of NiNO32 needed to react with 45 mL of K2CO3, you need to use the stoichiometry of the reaction. First, write and balance the chemical equation for the reaction. Then, use the molarity of K2CO3 to calculate the moles of K2CO3 present. Finally, use the balanced equation to find the volume of NiNO32 needed based on the stoichiometry of the reaction.
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
It takes 2 moles of NO to form 2 moles of NO2, so to form 4.67 moles of NO2 you would need 4.67 moles of NO.
If 2 moles of Na2CrO4 react completely, they will form the same number of moles of NaCl. This is because the mole ratio between Na2CrO4 and NaCl is 1:2. Therefore, 2 moles of Na2CrO4 will form 2 moles of NaCl.
The relative number of moles of hydrogen to moles of oxygen that react to form water represents the stoichiometry of the chemical reaction according to the balanced equation. This relationship reflects the proportions in which the reactants combine to form the products.
This is the amount of magnesium.
The ratio H/O is 2.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
For every 2 moles of A3, 3 moles of B2 react to form 6 moles of AB. Since we have 10 moles of A3, we need to double the moles of B2 reacting, which would be 15 moles of B2 to fully react with the 10 moles of A3. This would produce 30 moles of AB.
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
To determine the volume of NiNO32 needed to react with 45 mL of K2CO3, you need to use the stoichiometry of the reaction. First, write and balance the chemical equation for the reaction. Then, use the molarity of K2CO3 to calculate the moles of K2CO3 present. Finally, use the balanced equation to find the volume of NiNO32 needed based on the stoichiometry of the reaction.
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
no it wont sorry i dont know the answer but i tried it and it didnt work for it