no it wont sorry i dont know the answer but i tried it and it didnt work for it
From the balanced chemical equation 3Fe2O3 + CO → 2Fe3O4 + CO2, it can be seen that 3 moles of Fe2O3 react with 1 mole of CO to produce 2 moles of Fe. Therefore, if 25 moles of CO react, it will produce 25/3 * 2 = 16.67 moles of Fe.
mass / molar mass molar mass Fe2O3 = 159.69 g/mol mass Fe2)3 = 4.00 kg = 4000 g moles = 4000 g / 159.69 g/mol = 25.05 moles Fe2O3 The balanced equation tells you that 1 mole Fe2O3 requires 3 moles CO to react So 25.05 moles needs (3 x 25.05) moles CO = 75.15 moles Co is needed to react 4.00 kg Fe2O3 = 75.2 mol (3 sig figs) b) The equation tells you that 1 moles Fe2O3 reacts to form 2 moles Fe So 25.05 moles will form (2 x 25.05) mol Fe moles Fe formed = 50.10 moles = 50.1 mol (3 sig figs) The equation tells you 1 mole Fe2O3 reacts to form 3 moles CO2 So 25.05 mol Fe2O3 will form (3 x 25.05) mol CO2 = 75.15 moles CO2 = 75.2 mol (3 sig figs) ==
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
If 12 mol of CO and 12 mol of Fe2O3 are allowed to react, the limiting reactant will be CO. The balanced chemical equation is 3CO + Fe2O3 -> 2Fe + 3CO2, and since it takes 3 mol of CO to react with 1 mol of Fe2O3, there is excess Fe2O3 left after the CO is consumed.
To determine the grams of carbon needed to react with 2.50 moles of Fe2O3, you first need to balance the equation for the reaction between C and Fe2O3. Then, calculate the molar ratio between C and Fe2O3 from the balanced equation. Finally, use the molar mass of carbon to convert the moles of carbon to grams.
To calculate the grams of CO needed to react with Fe2O3, you need to write a balanced chemical equation for the reaction, determine the moles of Fe2O3 given the mass provided, and use the stoichiometry of the balanced equation to find the moles of CO needed. Finally, convert the moles of CO to grams using the molar mass of CO.
From the balanced chemical equation 3Fe2O3 + CO → 2Fe3O4 + CO2, it can be seen that 3 moles of Fe2O3 react with 1 mole of CO to produce 2 moles of Fe. Therefore, if 25 moles of CO react, it will produce 25/3 * 2 = 16.67 moles of Fe.
mass / molar mass molar mass Fe2O3 = 159.69 g/mol mass Fe2)3 = 4.00 kg = 4000 g moles = 4000 g / 159.69 g/mol = 25.05 moles Fe2O3 The balanced equation tells you that 1 mole Fe2O3 requires 3 moles CO to react So 25.05 moles needs (3 x 25.05) moles CO = 75.15 moles Co is needed to react 4.00 kg Fe2O3 = 75.2 mol (3 sig figs) b) The equation tells you that 1 moles Fe2O3 reacts to form 2 moles Fe So 25.05 moles will form (2 x 25.05) mol Fe moles Fe formed = 50.10 moles = 50.1 mol (3 sig figs) The equation tells you 1 mole Fe2O3 reacts to form 3 moles CO2 So 25.05 mol Fe2O3 will form (3 x 25.05) mol CO2 = 75.15 moles CO2 = 75.2 mol (3 sig figs) ==
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
If 12 mol of CO and 12 mol of Fe2O3 are allowed to react, the limiting reactant will be CO. The balanced chemical equation is 3CO + Fe2O3 -> 2Fe + 3CO2, and since it takes 3 mol of CO to react with 1 mol of Fe2O3, there is excess Fe2O3 left after the CO is consumed.
To determine the grams of carbon needed to react with 2.50 moles of Fe2O3, you first need to balance the equation for the reaction between C and Fe2O3. Then, calculate the molar ratio between C and Fe2O3 from the balanced equation. Finally, use the molar mass of carbon to convert the moles of carbon to grams.
Depict moles eg: Fe2O3(s) + 3CO(g)--> 2Fe(s) + 3CO2(g) 1 mole of Fe2O3 4 moles of CO 2 moles of Fe 3 moles of CO2
There are several different possible reactions of Fe2O3 with CO, depending on temperature and ratio of reactants. The simplest is probably Fe2O3 + CO ==>2FeO + CO21.00 Kg x 1000 g/Kg x 1 mole Fe2O3/160 g = 6.25 moles Fe2O3 moles CO2 produced = 6.25 moles CO2 Volume CO2 at STP = 6.25 moles x 22.4 L/mole = 140 Liters
If 1 mole of carbon reacts, 1 mole of CO is produced according to the balanced chemical equation for the reaction. Therefore, if 1.4 moles of carbon react, 1.4 moles of CO will be produced.
160...cant quite grasp HOW though
The balanced chemical equation for the reaction of CO with oxygen to form CO2 is: 2 CO + O2 -> 2 CO2. This means that 2 moles of CO produce 2 moles of CO2. Therefore, if you start with 3.60 moles of CO, it will produce 3.60 moles of CO2 when reacted with sufficient oxygen.
The balanced chemical equation shows that 5 moles of carbon react with 2 moles of sulfur dioxide to produce 2 moles of carbon disulfide and 4 moles of carbon monoxide. Therefore, to react with 5.44 moles of sulfur dioxide, you would need 5.44 moles / 2 moles = 2.72 moles of carbon.