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14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe
Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================
The rusting of iron has the reaction 4 Fe + 3 O2 equals 2 Fe2O3. So every 2 moles of iron produces 1 moles of iron oxide. 16.7 grams is .299 moles of iron. This means there are 0.149 moles of iron oxide or 23.88 grams.
To convert grams to moles you use the molar mass of iron (55.8 grams per mole). Divide the numbers to get the number of moles: 500 g Fe / 55.8 g/mol = 8.96 mol Fe. To calculate the number of atoms, use Avogadro's Number (6.02*1023). Multiply the number of moles and Avogadro's number: 8.96 mol * (6.02*1023) = 5.39*1024 Fe atoms.
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
55.8 * 0.750 = 41.85
Iron oxide is produced.The chemical reaction is given as 2Fe+3H20=Fe2O3+3H2
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe
Fe2O3 isn't a reaction it is Iron(III)oxide a.k.a. hematite or simply rust
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Fe2O3 + 2Al --> Al2O3 +2 Fe The reaction is commonly known as thermite for the enormous amount of heat produced. The iron produced by the reaction is molten.
Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================
The rusting of iron has the reaction 4 Fe + 3 O2 equals 2 Fe2O3. So every 2 moles of iron produces 1 moles of iron oxide. 16.7 grams is .299 moles of iron. This means there are 0.149 moles of iron oxide or 23.88 grams.
The thermite reaction usually has two reactants: Iron III oxide (Fe2O3, rust) and aluminum. Both reactants are in powdered form. The reaction equation is: Fe2O3 + 2Al --> Al2O3 + 2Fe The products are aluminum oxide (corundum) and molten iron.
Rust is a consequence of a chemical reaction: oxidation (reaction with oxygen) of iron and iron containing alloys. The oxide Fe2O3 (generally hydrated) is formed.
Reactants: iron an oxygen Product: iron(III) oxide, Fe2O3