The reaction is:
4 Fe + 3 O2 = 2 Fe2O3
The answer is 319,38 g.
79 grams
28g Fe
The mass of nitrous oxide is 262,8 g.
23.95g
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
Iron (III) oxide -> Iron + OxygenSteps to find the mass of iron obtained from 268g of iron (III) oxide:Step 1: Write the balanced equation2Fe2O3 -> 4Fe + 3O2Step 2: Identify key reactants and products2Fe2O3 -> 4FeStep 3: Write down the mole ratio2 moles : 4 molesStep 4: Change moles into gram formula mass2((2x56)+(3x16)) : 4(1x56)320g : 224gStep 5: Find out how many grams of iron will be produced for every gram of iron (III) oxide1 gram = 224/320 = 0.7gStep 6: Find out how many grams of iron will be produced for 268 grams of iron (III) oxide268 grams = (224/320)x268 = 187.6 gramsThe mass of iron produced from 268 grams of iron (III) oxide is 187.6 grams.
79 grams
Rusted iron is FeO, iron oxide. 63.8 grams FeO (1 mole FeO/71.85 grams)(6.022 X 1023/1 mole FeO) = 5.35 X 1023 atoms of iron oxide -------------------------------------------
26.20
28g Fe
155.2 g
The mass of nitrous oxide is 262,8 g.
i dont know help :C
23.95g
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
The complete question: Lead (II) oxide reacts with ammonia forming solid lead nitrogen gas and liquid water. 1.)How many grams of ammonia are consumed in the reaction of 75.0g lead (II) oxide? 2.) If 56.4g of lead are produced how many grams of nitrogen are also formed?
The molecular mass of iron(III) chloride is 55.8 + 3(35.5) = 162.3 Amount of iron (III) chloride in a 80.5g pure sample = 80.5/162.3 = 0.496mol