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The reaction is:
4 Fe + 3 O2 = 2 Fe2O3
The answer is 319,38 g.

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Q: How many grams of iron oxide are produced from 8.00 mol of iron?
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How many grams of iron can be obtained from a 268g sample of iron 3 oxide?

Iron (III) oxide -> Iron + OxygenSteps to find the mass of iron obtained from 268g of iron (III) oxide:Step 1: Write the balanced equation2Fe2O3 -> 4Fe + 3O2Step 2: Identify key reactants and products2Fe2O3 -> 4FeStep 3: Write down the mole ratio2 moles : 4 molesStep 4: Change moles into gram formula mass2((2x56)+(3x16)) : 4(1x56)320g : 224gStep 5: Find out how many grams of iron will be produced for every gram of iron (III) oxide1 gram = 224/320 = 0.7gStep 6: Find out how many grams of iron will be produced for 268 grams of iron (III) oxide268 grams = (224/320)x268 = 187.6 gramsThe mass of iron produced from 268 grams of iron (III) oxide is 187.6 grams.

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