55.8 * 0.750 = 41.85
45
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
4Fe + 3O2 -> 2Fe2O3 is the balanced equation.It'll need enough oxygen (> (0.46*3)/4 mole O2)to give (0.46*2)/4 mole Fe2O3, so 0.23 mole Fe2O3is produced.
Fe2O3 + 2Al --> Al2O3 +2 Fe The reaction is commonly known as thermite for the enormous amount of heat produced. The iron produced by the reaction is molten.
decomposition of Al2O3
81.93%
exothermic reaction! (sudenly?)
Aluminum oxide, Al2O3 would produce aluminum by the following decomposition:2Al2O3 ==> 4Al + 3O2 750.0 g Al2O3 x 1 mole/101.96 g = 7.356 moles Al2O3 Theoretical yield of Al = 7.356 moles Al2O3 x 4 moles Al/2 mole Al2O3 = 14.71 moles Al Theoretical mass of Al = 14.71 moles Al x 26.98 g/mole = 396.9 g Al Percent yield = 256.734 g/396.9 g (x100%) = 64.68% yield (to 4 significant figures)
temperatures above 1100 °C kyanite decomposes into mullite and vitreous silica via the following reaction: 3(Al2O3·SiO2) → 3Al2O3·2SiO2 + SiO2
A passive aluminum oxide layer will form on the surface of the aluminum, when it is in the presence of Oxygen (Al2O3). This then goes on to protect the rest of the aluminum from further oxidisation as the layer will remain in place, bonded to the aluminum.
The reaction is with aluminium:Fe2O3 + 2 Al = 2 Fe + Al2O3
MgO2