The easiest way to approach this is to remember molar volume: one mole of every (ideal) gas will occupy 22.4 liters at STP - a gas occupies 22.4 L/mol.
Since we know that, we can set up a simple proportion that follows the thought process: if one mole of a gas occupies 22.4 liters (at STP), then 2.88 grams of methane occupies x liters.
But before we do that, we have a problem: the measurement given is in the wrong units - it is in grams when molar volume is in moles. Therefore, we first need to convert 2.88 grams of methane to moles. To do this, we need the molar mass of the compound - the sum of all the atomic masses involved.
Carbon = 12.0 grams
Hydrogen = 1.01 grams × 4 atoms = 4.04 grams
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Methane = 16.04 grams
To convert grams to moles:
Grams of substance ÷ Molar mass (in grams) = Moles of substance
2.88 grams CH4 ÷ 16.04 grams CH4 = 0.180 moles CH4
Now we follow through with our proportion:
22.4 L/1 mol = x L/.180 mol
x = 4.03 L
2.88 grams of methane occupies 4.03 liters at STP
38.0 g F2 = 1.00 mole F2 (divide 38.0 by molar mass= 2*19.00 g/mol)
At STP each (1.00) mole of ANY gas will occupy 22,4 Litre.
The volume of methane is 83,84 L.
130L
How many molecules are in 30 liters of methane (CH4) at STP
The amount of oxygen is 0,067 moles.
One mole has a volume of 22.4l.So the volume is 224ml
This volume is 65,68 L.
CH4 + 2 O2 -> CO2 + 2 H2O So for every L of CH4 you need 2 L of O2 So for 50L of CH4 you need 100L O2
How many molecules are in 30 liters of methane (CH4) at STP
The amount of oxygen is 0,067 moles.
One mole has amass of 16g.There are 6.428mol.Its mass is 102.85g
This volume is 79,79 litres.
One mole has a volume of 22.4l.So the volume is 224ml
This volume is 65,68 L.
CH4 + 2 O2 -> CO2 + 2 H2O So for every L of CH4 you need 2 L of O2 So for 50L of CH4 you need 100L O2
54 liters at STP (standard temperature and pressure)
0.48 liters at STP (standard temperature and pressure)
Density: BF3 = 0.00276 g/cm3 (anhydrous gas)Volume: 0.155 (g) / 0.00276 (g/cm3) = 56.16 = 56.2 cm3 (gas volume at STP)
9.75 L
Molecular formula for methane is CH4.. Then, molecular mass of methane = 12 + 4 x 1 = 16 u. 1 mole of methane = 16 g = 22.4 L at STP. Therefore, weight of one litre of methane = 16/22.4 g = 0.714 g.