The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
One mole of sulfur reacts with 1.5 moles of oxygen to produce one mole of sulfur trioxide. So, with two moles of sulfur and three moles of oxygen, the limiting reactant is sulfur. Therefore, two moles of sulfur will produce two moles of sulfur trioxide.
In one mole of hydrogen peroxide (H2O2), there are two moles of oxygen atoms.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
PV = nRTV = nRT/P = (2moles)(0.0821 Latm/Kmol)(300K)/1.3 atm V = 37.9 liters = 38 liters (2 significant figures)
4 moles of oxygen atoms are present in 4 moles of H2O
One mole of sulfur reacts with 1.5 moles of oxygen to produce one mole of sulfur trioxide. So, with two moles of sulfur and three moles of oxygen, the limiting reactant is sulfur. Therefore, two moles of sulfur will produce two moles of sulfur trioxide.
In one mole of hydrogen peroxide (H2O2), there are two moles of oxygen atoms.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
PV = nRTV = nRT/P = (2moles)(0.0821 Latm/Kmol)(300K)/1.3 atm V = 37.9 liters = 38 liters (2 significant figures)
4 moles of oxygen atoms are present in 4 moles of H2O
The volume of hydrogen should be twice the volume of oxygen formed in the electrolysis of water because the ratio of the number of moles of hydrogen to oxygen in water is 2:1. This is based on the molecular formula of water, H2O, where each water molecule contains two hydrogen atoms and one oxygen atom.
The number of moles in exactly 64 grams of oxygen (O2) is two.
moles = mass/molar mass The molar mass of an oxygen atom = 16 g mol-1, as there are two oxygen atoms in diatomic oxygen this has to be doubled. 42g / 32g mol-1 = 1.3125 moles
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
0.75 moles of any substance is 0.75(6.02x1023) = 4.52x1023 particles. If those particles are CO2 molecules, and each molecule has 2 oxygen atoms, then it's 2(4.52x1023) = 9.04x1023 oxygen atoms.
For every mole of oxygen consumed in the reaction 2H2 + O2 -> 2H2O, two moles of water are produced. Therefore, if 0.633 moles of oxygen are consumed, the number of moles of water produced would be 2 x 0.633 = 1.266 moles.