mg br3
BrO2
CaBr2 :)
If it tells you to find the empirical formula when percent composition is given or if the mass of each element is given in a specific compound.
FeO2
Fe2S3, I think...
BrO2
C2H5Br
CaBr2 :)
MgO
Chi a+
The atomic mass of lithium is 6.94, while that for bromine is 79.90. 7.9/6.94 = 1.095 and 92.1/79.90 = 1.15. the closest integer ratio between these two number si 1:1, so the empirical formula is LiBr.
CHI3
Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.
P2o5
CCl4
Because unlike the empirical formula, the molecular formula does not have to be the simplest ratio.If by chance you are given the percent composition of the elements in a substance, you could calculate the empirical formula and then the empirical formula's mass. However, the molecular formula equation is molecular formula= (empirical formula)n, where n is the mass of the molecular formula divided by the mass of the empirical formula. You would, therefore, need to know the mass belonging to the molecular formula, which you are not given.
Cr3Si2 is the empirical formula for a compound containing chromium and silicon an has 73.52 mass percent chromium.