2Pb(NO3)2---> 2PbO + 4NO2 + O2
2Pb(NO3)2 when heated produces 2PbO+NO2+O2
for the part that says "when heated produces" substitute it with an arrow and then you"ll have the equation
Chemical formula for water is H2O and for lead nitrate is Pb(NO3). Lead nitrate simply dissolves in water and making water poisonous.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The word equation would be iron reacts with lead nitrate to form iron two nitrate and lead.Or perhaps you meant this?The word equation would be Iron + Lead Nitrate => Iron (II) Nitrate + LeadThe chemical equation would be Fe(s) + Pb(NO3)2 => Fe(NO3)2 + PbI assume you are having problems with the charge the iron nitrate would go into, so here is a link that helps describe how to determine the charges of the ions of transitional metals: http://indiescience.org/basetalk/index.php?topic=13.0
Lead (II) Nitrate
The net ionic equation for barium chloride (BaCl2) and lead acetate (Pb(C2H3O2)2) is Ba²⁺ + 2C2H3O2⁻ → Ba(C2H3O2)2. This equation represents the formation of barium acetate as a solid precipitate when barium chloride and lead acetate are mixed together.
The balanced equation for the decomposition of lead(II) nitrate is: 2Pb(NO3)2(s) → 2PbO(s) + 4NO2(g) + O2(g).
the equation for the decomposition of lead ii nitrate by heating is: 2Pb(NO3)2 - - - ->2PbO + 4NO2 + O2
Chemical formula for water is H2O and for lead nitrate is Pb(NO3). Lead nitrate simply dissolves in water and making water poisonous.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The balanced equation for the decomposition of lead (II) oxide (PbO) is: 2PbO -> 2Pb + O2
The correct chemical formula for lead nitrate is Pb(NO3)2.
Nickel(II) Nitrate --Δ--> Nickel(II) oxide + Nitrogen dioxide + Oxygen2 Ni(NO3)2 --Δ--> 2 NiO + 4 NO2 + O2
A thermal decomposition reaction occur: lead oxide, nitrogen dioxide and oxygen are obtained.
When 2 g of lead nitrate powder is heated, it undergoes thermal decomposition to form lead oxide, nitrogen dioxide gas, and oxygen gas. The balanced chemical equation for this reaction is: 2 Pb(NO3)2(s) -> 2 PbO(s) + 4 NO2(g) + O2(g).
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
Lead reacts with hydrogen nitrate to form lead(II) nitrate and hydrogen gas. The balanced chemical equation for this reaction is: Pb + 4HNO3 → Pb(NO3)2 + 2H2
Pb(NO3)2