2Pb(NO3)2---> 2PbO + 4NO2 + O2
2Pb(NO3)2 when heated produces 2PbO+NO2+O2
for the part that says "when heated produces" substitute it with an arrow and then you"ll have the equation
Chemical formula for water is H2O and for lead nitrate is Pb(NO3). Lead nitrate simply dissolves in water and making water poisonous.
Stardust
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
lead II acetate and barium chloride equation
The word equation would be iron reacts with lead nitrate to form iron two nitrate and lead.Or perhaps you meant this?The word equation would be Iron + Lead Nitrate => Iron (II) Nitrate + LeadThe chemical equation would be Fe(s) + Pb(NO3)2 => Fe(NO3)2 + PbI assume you are having problems with the charge the iron nitrate would go into, so here is a link that helps describe how to determine the charges of the ions of transitional metals: http://indiescience.org/basetalk/index.php?topic=13.0
the equation for the decomposition of lead ii nitrate by heating is: 2Pb(NO3)2 - - - ->2PbO + 4NO2 + O2
Chemical formula for water is H2O and for lead nitrate is Pb(NO3). Lead nitrate simply dissolves in water and making water poisonous.
Lead(II) Nitrate is Pb(NO3)2
Pb(NO3)2
Stardust
Nickel(II) Nitrate --Δ--> Nickel(II) oxide + Nitrogen dioxide + Oxygen2 Ni(NO3)2 --Δ--> 2 NiO + 4 NO2 + O2
Decomposition reaction(of Lead(II) nitrate) takes place. It decomposes into Yellow Lead(II) oxide, Reddish-orange Nitrogen dioxide and Oxygen
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
For lead (II) nitrate: H2SO4 + Pb(NO3)2 -----> 2HNO3 + PbSO4 ...................................................(white)
lead II acetate and barium chloride equation
Lead(II) nitrate and potassium iodide are solids.
The formula for lead (II) nitrate is Pb(NO3)2.