Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The chemical formula of lead(II) nitrate is Pb(NO3)2; also exist the lead(IV) nitrate but not the lead(III) nitrate.
The net ionic equation for the reaction between aqueous potassium iodide (KI) and aqueous lead(II) nitrate (Pb(NO3)2) is: 2I- (aq) + Pb2+ (aq) → PbI2 (s)
The chemical formula of lead(II) nitrate is Pb(NO3)2. The chemical formula of hydrogen sulfide is H2S.
2NH4Cl (aq) + Pb(NO3)2 (aq) ----> 2NH4NO3 (aq) + PbCl2 (s)
The formula for lead (II) nitrate is Pb(NO3)2.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The molecular formula of lead(II) nitrate is Pb(NO3)2, and the molecular formula of sodium nitrate is NaNO3. Lead(II) nitrate contains one lead atom, two nitrate ions (NO3-), while sodium nitrate contains one sodium atom and one nitrate ion.
The chemical formula of lead(II) nitrate is Pb(NO3)2. The solution don't change the formula - but in the solution exist the anion (NO3)- and the cation Pb2+.
The net ionic equation for the reaction of aqueous potassium iodide with aqueous lead (II) nitrate is: 2I⁻(aq) + Pb²⁺(aq) -> PbI₂(s)
Lead(II) nitrate and sodium iodide undergo a double displacement reaction to form sodium nitrate and lead(II) iodide, which is a slightly soluble yellow solid. The balanced chemical equation for this reaction is: Pb(NO3)2(aq) + 2NaI(aq) -> 2NaNO3(aq) + PbI2(s)
The chemical formula of lead(II) nitrate is Pb(NO3)2; also exist the lead(IV) nitrate but not the lead(III) nitrate.
The chemical formula of lead(II) nitrate is Pb(NO3)2.
The chemical formula of lead(II) nitrate is Pb(NO3)2.
The correct formula for the product of lead(II) nitrate reacting with sodium iodide is lead(II) iodide, which has the formula PbI2. This is because lead(II) ions from lead(II) nitrate react with iodide ions from sodium iodide to form lead(II) iodide as the product.
The net ionic equation for the reaction between aqueous potassium iodide (KI) and aqueous lead(II) nitrate (Pb(NO3)2) is: 2I- (aq) + Pb2+ (aq) → PbI2 (s)
The formula for lead(II) nitrate is Pb(NO3)2.