AL3 plus and O2 negative will form Aluminum Oxide. It has many names such as corundum and alumina. It is an amphoteric oxide.
The formula for the ionic compound formed between S^2- and Pb^4+ is PbS2, where lead (Pb) has a 4+ charge and sulfur (S) has a 2- charge. This results in the compound lead(IV) sulfide.
In order to form a neutral ionic compound, one K ion (with a +1 charge) would combine with two S2- ions (each with a -2 charge). Therefore, one formula unit of the compound would contain 1 K ion and 2 S2- ions.
The ionic compound formed from potassium and sulfur is potassium sulfide (K2S). Potassium has a +1 charge, and sulfur has a -2 charge, so two potassium ions (K+) combine with one sulfur ion (S2-) to form a stable compound held together by ionic bonds.
The chemical formula for the ionic compound formed from aluminum and sulfur is Al2S3. This compound is formed by the transfer of electrons between aluminum (Al) and sulfur (S) atoms, resulting in the formation of Al3+ and S2- ions which combine in a 2:3 ratio to create Al2S3.
The ionic compound formed between calcium and sulfur is calcium sulfide, with the chemical formula CaS. In this compound, calcium has a 2+ charge and sulfur has a 2- charge, resulting in a neutral combination.
The ionic formula for Al3+ is Al^3+ and for S2- is S^2-. When these two ions combine, they form the ionic compound Al2S3.
The formula for the ionic compound formed from Al^3+ and S^2- ions will be Al2S3. This is because the charges must balance out, requiring two Al^3+ ions for every three S^2- ions to cancel out the charges and form a neutral compound.
The correct formula for a compound combining Al³⁺ and S²⁻ is Al₂S₃. This is determined by balancing the charges of the ions so that they cancel out in the compound.
The ionic formula for Ca2+ and S2- is CaS, which is calcium sulfide. In this compound, calcium donates two electrons to sulfur, forming a ionic bond between the two elements.
The formula for the ionic compound formed from lead (Pb2+) and sulfur (S2-) ions is PbS, with a 1:1 ratio of cations to anions. Lead has a 2+ charge while sulfur has a 2- charge, so they combine in a 1:1 ratio to form a neutral compound.
3S2- + 2Sc3+ --> Sc2S3name: Scandium sulfide
The formula for the ionic compound formed between S^2- and Pb^4+ is PbS2, where lead (Pb) has a 4+ charge and sulfur (S) has a 2- charge. This results in the compound lead(IV) sulfide.
In order to form a neutral ionic compound, one K ion (with a +1 charge) would combine with two S2- ions (each with a -2 charge). Therefore, one formula unit of the compound would contain 1 K ion and 2 S2- ions.
The ionic bond formula between calcium and sulfur is CaS, where calcium loses 2 electrons to form Ca2+ cation and sulfur gains 2 electrons to form S2- anion. This results in the formation of an ionic compound called calcium sulfide.
The formula for the ionic compound formed between zinc and sulfur is ZnS, which is known as zinc sulfide. In this compound, zinc has a 2+ charge (Zn2+) and sulfur has a 2- charge (S2-), so they combine in a 1:1 ratio to form a neutral compound.
The ionic compound formed between Pb2+ and S2- ions is lead(II) sulfide, with the chemical formula PbS. Lead(II) has a 2+ charge while sulfide has a 2- charge, making the compound electrically neutral.
The ionic compound formed from potassium and sulfur is potassium sulfide (K2S). Potassium has a +1 charge, and sulfur has a -2 charge, so two potassium ions (K+) combine with one sulfur ion (S2-) to form a stable compound held together by ionic bonds.