Thallium is an element on the Periodic Table. It's atomic number is 81.
Because it is an element, I don't understand what you mean by "its formula".
The symbol for Thallium is Tl, so the formula would be Tl...
If you want the formula for a compound with thallium, that's a different story.
It is not a diatomic element, if that's what you meant.
For more information on thallium, go to
http://en.wikipedia.org/wiki/Thallium
The formula of Nitrogen III sulfide is NS3.
The chemical formula of gold(III) sulfide is Au2S3.
Co2S3 is the formula for cobalt (III) sulfide.
Chromium III is Cr3+. The roman numeral tells you the charge. Sulfide is S2-. You can figure this out from the periodic table. Sulfur needs two electrons to be like Argon, the next noble gas. When they form a compound, they combine in a ratio such that the total positive charge balances the total negative charge. 2 Cr3+ ions have a total charge of +6. 3 S2- ions have a total charge of -6. So the formula is Cr2S3.
Yes, when cobalt(III) bromide reacts with potassium sulfide, it will form cobalt(III) sulfide as a solid precipitate, as cobalt(III) sulfide is insoluble in water.
The formula of Nitrogen III sulfide is NS3.
Thallium(III) nitrate is Tl(NO3)3. Thallium(I) nitrate is TlNO3.
The chemical formula for gold (III) sulfide is Au2S3.
The chemical formula of gold(III) sulfide is Au2S3.
Ni2S3
Co2S3also written asCo_2_S_3_sulfide 2- charge trades with the Cobalt 3+ charge
Co2S3 is the formula for cobalt (III) sulfide.
Thallium(III) Selenide
This compound is thallium(III) hydroxide.
Ferrous Sulfide = Iron (III) Sulfide Both -> Fe2S3
The two main oxidation states of thallium are +1 and +3. In the oxidation state +1 most compounds closely resemble the potassium or the silver compounds (The ionic radius of thallium(I) is 1.47 Å while that of potassium is 1.33 Å and that of silver is 1.26 Å). For example, the water-soluble and very basic thallium(I) hydroxide reacts with carbon dioxide forming water-soluble thallium carbonate This carbonate is the only water soluble heavy metal carbonate. The similarity with silver compounds is observed with the halide, oxide, and sulfide compounds. Thallium(I) bromide is a photosensitive yellow compound very similar to the silver bromide, while the black thallium(I) oxide and thallium(I) sulfide are very similar to the silver oxide and silver sulfide. The compounds with oxidation state +3 resemble the aluminium(III) compounds. They are moderately strong oxidizing agents, as illustrated by the reduction potential of +0.72 volts for Tl3+ + 3 e- → Tl(s). The thallium(III) oxide is a black solid which decomposes above 800 °C, forming the thallium(I) oxide and oxygen.[4]
Chromium III is Cr3+. The roman numeral tells you the charge. Sulfide is S2-. You can figure this out from the periodic table. Sulfur needs two electrons to be like Argon, the next noble gas. When they form a compound, they combine in a ratio such that the total positive charge balances the total negative charge. 2 Cr3+ ions have a total charge of +6. 3 S2- ions have a total charge of -6. So the formula is Cr2S3.