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(1.0*10^-14)/(1.6*10^-1)= Kb

Kb=6.25*10^-14

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13y ago
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11y ago

+1 for H

-2 for each O

+5 for I

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6y ago

The iodate anion has the formula IO4^- so the oxidation number for iodine is 7+

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13y ago

Formula: IO3-

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11y ago

-2 for each Oxygen, +5 for iodine

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8y ago

This is tha anion I-.

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15y ago

IO3-

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13y ago

it is IO3-

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11y ago

IO3-

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Q: What is the formula for the iodate anion?
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