What is the formula for this covalent compound iodine pentafluoride?

Answer 1

The formula for iodine pentafluoride is IF5. This compound is formed when one iodine atom bonds with five fluorine atoms through covalent bonds. In this compound, iodine has a +1 oxidation state, while each fluorine atom has a -1 oxidation state, resulting in a neutral molecule.

Answer 2

Iodine pentafluoride, IF5, is a fluoride of iodine. It is a colourless or yellow liquid with a density of 3250 kg m−3. It was first synthesized by Henri Moissan in 1891 by burning solid iodine in fluorine gas.[3] This exothermic reaction is still used to produce iodine pentafluoride, although the reaction conditions have been improved.[4][5] An alternative IUPAC name is pentafluoro-λ5-iodane.

Answer 3

Iodine pentafluoride is molecular. It has a pyramidal shape. It is a reactive compound which is a colourless liquid at room temperature.

Molecular compounds are formed between two non-metals. Both iodine and fluorine are non-metals. The formula for the compound would be IF5.

Answer 4

The formula for iodine pentafluoride is IF5. It consists of one iodine atom bonded to five fluorine atoms.

Answer 5

The molecular formula for iodine pentafluoride is IF5.

Answer 6

The formula for Iodine Pentafluoride is IF5

Answer 7

iodine penta flouride is AB5E type one lone pair will occupy one corner of octahedron so the structure will become square pyramidal Also I like boys.

Answer 8

Most interhalogens are covalent.

Answer 9

The chemical formula of iodine pentafluoride is IF5.

Answer 10

Iodine is a halogen. Halogens are one electron away from being a noble gas. Thus, they all have 7 valence electrons.