if both are aqueous solutions it should react to form precipitates of solid barium sulfate and solid silver chloride.
Ag2SO4 + BaCl2 --> 2AgCl + BaSO4
The word equation for silver nitrate plus sodium chloride is "silver nitrate + sodium chloride → silver chloride + sodium nitrate". The symbol equation for this reaction is "AgNO3 + NaCl → AgCl + NaNO3".
When barium chloride reacts with silver nitrate, a white precipitate of silver chloride is formed due to the double displacement reaction between the two compounds. This reaction is a classic example of a precipitation reaction, where insoluble silver chloride is formed as a product while barium nitrate remains in solution.
To find the limiting reactant, we need to determine how many grams of silver chloride can be produced from each reactant and compare the results. Calculate the amount of silver chloride that can be produced from 10.0 g of silver nitrate. Calculate the amount of silver chloride that can be produced from 15.0 g of barium chloride. The reactant that produces the lesser amount of silver chloride will be the limiting reactant.
You can determine which ions are present in the water sample by conducting specific tests for each ion. For nitrate ions, you can use a nitrate test kit that typically involves a colorimetric reaction. For chloride ions, an addition of silver nitrate solution will form a white precipitate of silver chloride. Sulfate ions can be detected by adding barium chloride solution, yielding a white precipitate of barium sulfate.
The net ionic equation for silver nitrate and sodium chloride is: Ag⁺(aq) + Cl⁻(aq) → AgCl(s) This equation shows the formation of a white precipitate of silver chloride when silver nitrate and sodium chloride are mixed together in aqueous solution.
This equation is 3 BaCl2 + 2 Ag3PO4 -> Ba3(PO4)2 + 6 AgCl.
When silver nitrate is added to barium chloride, a white precipitate of silver chloride forms because silver chloride is insoluble in water. This occurs due to a double displacement reaction where the silver ions from silver nitrate react with the chloride ions from barium chloride to form silver chloride. The remaining solution would contain barium nitrate as the other product of the reaction.
9.11 g
The word equation for silver nitrate plus sodium chloride is "silver nitrate + sodium chloride → silver chloride + sodium nitrate". The symbol equation for this reaction is "AgNO3 + NaCl → AgCl + NaNO3".
The balanced chemical equation for this reaction is: BaCl2 (aq) + 2AgNO3 (aq) → 2AgCl (s) + Ba(NO3)2 (aq). Silver chloride is insoluble in water and forms a white precipitate, while barium nitrate remains in solution.
Balanced: 2AgNO3 + CaCO2 ---> 2AgCO + Ca(NO3)2 Unbalanced: AgNO3 + CaCO2 ---> AgCO + Ca(NO3)2
The reaction between silver nitrate and sodium chloride forms silver chloride and sodium nitrate. The balanced equation is: AgNO3 + NaCl → AgCl + NaNO3
When silver nitrate reacts with sodium chloride, silver chloride is formed according to the equation: AgNO3 + NaCl -> AgCl + NaNO3. The molar ratio of silver nitrate to silver chloride is 1:1. Therefore, 100 g of silver nitrate will produce 143.32 g of silver chloride.
When barium chloride reacts with silver nitrate, a white precipitate of silver chloride is formed due to the double displacement reaction between the two compounds. This reaction is a classic example of a precipitation reaction, where insoluble silver chloride is formed as a product while barium nitrate remains in solution.
LiI(aq) + AgNO3(aq) --> AgI(s) + LiNO3(aq)
Examples: silver nitrate, barium chloride, sodium carbonate.
The balanced equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) is: AgNO3 + NaCl → AgCl + NaNO3