1170g
39.81% Cu20.06% S?% OFirst you have to find the percent of oxygen in the compound. All you have to do is add the remaining percent to make it equal to 100%.100 - 39.81 - 20.06 = 40.13% oxygenFind the atomic weights for each element. Take the percents and take off the percent sign and switch it to grams. Then divide the percents with the atomic mass to get moles.Atomic masses:Cu- 63.5S- 32.1O- 16.0percent / atomic mass = # molesCu 39.81g / (63.5g) = .627 molesS 20.06g / (32.1g) = .625 molesO 40.13g (16.0g) = 2.51 molesFind the ratio of Cu:S:O (it doesn't matter what order). In order to do this, divide all numbers by the smallest number (.625).S .625 / .625 = 1Cu .627 / .625 = 1O 2.51 / .625 = 4.02When doing empirical formulas, all digits are uncertain to the effect of +/- .02So we can say that oxygen is really 4. Therefore, the atoms are in a ratio of 1:1:4 making the empirical formula: Cu1S1O4 or CuSO4Looking at the empirical formula, we can say that it is probably the real formula because it forms a copper ion (Cu) and a sulfate ion (SO4). Also, the name is Copper (II) sulfate
Inconel Alloy 625 A nickel-chromium-molybdenum alloy with an addition of niobium that acts with the molybdenum to stiffen the alloy's matrix and thereby provide high strength without a strengthening heat treatment. The alloy resists a wide range of severely corrosive environments and is especially resistant to pitting and crevice corrosion. Used in chemical processing, aerospace and marine engineering, pollution-control equipment, and nuclear reactors
The Forest City Historical Association is located in Forest City, California at 625 Main Street. This historical association aims to preserve and showcase the history of Forest City and surrounding areas.
Felsic rocks have the lowest melting point, ranging from 600 to 750 degree Celsius. Felsic rocks are light colored and their melts don't consist of enough magnesium, iron and calcium to produce pyroxene, olivine or calcium plagioclase.
The exhaust system of a DG (diesel generator) set is a critical component that expels the engine's exhaust gases. It typically consists of an exhaust manifold, muffler, and exhaust pipe, which work together to reduce noise levels and direct harmful fumes away from the generator. Regular inspection and maintenance of the exhaust system are essential to ensure efficient operation and compliance with safety regulations.
There are 0.625 grams in 625 milligrams. You can convert milligrams to grams by dividing the milligrams by 1000.
1 milligram (mg) = .001 grams (g) = 1/1000 grams Therefore, 625 mg * 1/1000 grams = .625 g which is less than 1 gram (g).
0.625 Gram = 625 milligram
625 grams is 22.05 ounces.
If you think to ethanol the mass is 1, 973 625 g at 20 0C.
In the metric system, the prefix "m" means 10-3 and "g" means grams. Therefore, 625 mg of anything = 0.625 grams.
There are 1000 grams in one kilogram. Therefore, 625 grams is equal to 625/1000 = 0.625, or five eighths, of a kilogram.
5 kilograms = 5,000 grams 12.5 % of 5,000 = 625 grams.
Specific gravity is the ratio of the mass of some volume of substance to the mass of same volume of water. Here 0.25 kg ie 2500 g is the mass of some volume of given substance. The volume of water displaced is 625 mL ie 625 cc. 1 cc of water has a mass 1g. So 625 mL has 625 g. Hence the specific gravity is 2500/625 = 4 (no unit)
If u mean 25 ounces, there should be 625 grams.
39.81% Cu20.06% S?% OFirst you have to find the percent of oxygen in the compound. All you have to do is add the remaining percent to make it equal to 100%.100 - 39.81 - 20.06 = 40.13% oxygenFind the atomic weights for each element. Take the percents and take off the percent sign and switch it to grams. Then divide the percents with the atomic mass to get moles.Atomic masses:Cu- 63.5S- 32.1O- 16.0percent / atomic mass = # molesCu 39.81g / (63.5g) = .627 molesS 20.06g / (32.1g) = .625 molesO 40.13g (16.0g) = 2.51 molesFind the ratio of Cu:S:O (it doesn't matter what order). In order to do this, divide all numbers by the smallest number (.625).S .625 / .625 = 1Cu .627 / .625 = 1O 2.51 / .625 = 4.02When doing empirical formulas, all digits are uncertain to the effect of +/- .02So we can say that oxygen is really 4. Therefore, the atoms are in a ratio of 1:1:4 making the empirical formula: Cu1S1O4 or CuSO4Looking at the empirical formula, we can say that it is probably the real formula because it forms a copper ion (Cu) and a sulfate ion (SO4). Also, the name is Copper (II) sulfate
625 grams of water is 2.756 cups625 grams of water is 2.756 cups