Ammonia contains about 82.35 % nitrogen by mass.
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
71%
Ammonia-NH3 2N+3H2=2NH3 2moles of Nitrogen produced 2moles of Ammonia (2*14)g of Nitrogen produced (2*17)g of Ammonia 28g of Nitrogen produced 34g of Ammonia 34g of Ammonia is produced by 28g of Nitrogen 0.034kg of Ammonia is produced by 0.028kg of Nitrogen 91.3kg of Ammonia will be produced by 0.028*91.3/0.034 91.3kg of Ammonia will be produced by 75.19kg of Nitrogen FOR HYDROGEN: 3moles of H2 produces 2moles of NH3 (2*3)g H2 produces 2*17g NH3 6g hydrogen produces 34g ammonia 0.006kg hydrogen produces o.o34kg ammonia 91.3kg ammonia will be produced by 91.3*0.006/.034=16.11kg of Hydogen Therefore, 75.19kg of Nitrogen and 16.11kg of Hydrogen will produce 91.3kg of Ammonia
yes
Ammonification is the decomposition of nitrogen containing molecules into ammonia.
NH3 which is ammonia has the highest percentage by mass of nitrogen.
it can be calculated using the formula percentage composition of N =Gram molecular mass of nitrogen in the compound/ Gram molecular mass of compound *100
Mass of ammonia is 17. Mass of Hydrogen in it is 3. So the percentage of hydrogen by mass is 17.64%
The formula for ammonia is NH3, and to a reasonable approximation, the atomic weight of hydrogen is 1 and that of nitrogen is 14. Therefore, the % hydrogen = 100(3/17) = 18 %.
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
The percentage of nitrogen in aluminium nitrate is 19,72 %.
Molar mass of ammonia = (14.01 + 3.03) (Molar mass of nitrogen + 3 times molar mass of hydrogen, as chemical formula of ammonia is NH3). Molar mass= 17.04 Molar mass x moles = mass 17.04 x 3 = 51.12 Mass of 3 moles of ammonia is 51.12g.
88
71%
Ammonia-NH3 2N+3H2=2NH3 2moles of Nitrogen produced 2moles of Ammonia (2*14)g of Nitrogen produced (2*17)g of Ammonia 28g of Nitrogen produced 34g of Ammonia 34g of Ammonia is produced by 28g of Nitrogen 0.034kg of Ammonia is produced by 0.028kg of Nitrogen 91.3kg of Ammonia will be produced by 0.028*91.3/0.034 91.3kg of Ammonia will be produced by 75.19kg of Nitrogen FOR HYDROGEN: 3moles of H2 produces 2moles of NH3 (2*3)g H2 produces 2*17g NH3 6g hydrogen produces 34g ammonia 0.006kg hydrogen produces o.o34kg ammonia 91.3kg ammonia will be produced by 91.3*0.006/.034=16.11kg of Hydogen Therefore, 75.19kg of Nitrogen and 16.11kg of Hydrogen will produce 91.3kg of Ammonia
No. There are several oxides of nitrogen; none of which are ammonia. Ammonia is NH3, a compound of nitrogen and hydrogen.
The gram molecular mass of ammonia is 17.03. The formula shows that only one atom of nitrogen is required for each mole of ammonia; 4.12 mol of diatomic nitrogen contains 8.24 mol of nitrogen atoms, and with excess H, all of this nitrogen can be converted to ammonia. Therefore, 8.24 mol of ammonia can be produced, and multiplying this number by17.03 yields a total mass of 140.3 grams of ammonia, to the justified number of significant digits.