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Assuming by "room temperature" you mean about 77 °F (25 °C), the vapor pressure of methanol at saturation would be about 158 mmHg.

= 0.211 bar

= 21.1 kPa

= 0.208 atm

= 3.05 psia

You can estimate the vapor pressure using the formula

log10(P) = -(0.05223)a/T + b

where P is in mmHg, T is in kelvins, a = 38324, and b = 8.8017

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