The formula is:
NaOH(aq) + HCl(aq) --> NaCl + H2O(l)
So the ratio is:
1 : 1 : 1 : 1
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
The atomic ratio between sodium and chlorine in sodium chloride is 1:1, as indicated by its formula NaCl. If the mass ratio is wanted, it is that of the atomic weights of the two elements.
Saline.
It produces, 1 mole of the cation, Na + 1 mole of the anion, Cl -
23 g of sodium to 35.5 g Chlorine
One mole solution of sodium chloride makes 1000 millimole. So 0.1 mole solution of sodium chloride will have 100 millimole in the solution.
This question can be answered with the equation n = m ÷ M (where n is the number of mol's, m is te mass in grams and M is the Molar Mass of Sodium Chloride). Now, sodium chloride's molecular formula is written as, NaCl Now if we think of this formula as representing a ratio of elements within the compound, we can see that, NaCl : Cl = 1 mole of sodium chloride molecules : 1 mole of Chloride atoms So, as we know the mol ratio for this molecule, we can establish the mass of sodium in 11.7g of sodium chloride by first calculating the number of moles of Sodium chloride in 11.7g of the substance, so then moles = mass of sodium chloride ÷ Molar mass of sodium chloride = 11.7 ÷ 58.44277 = 0.20019584971759552122529442050745 moles (note that in stochiometry i personally prefer not to round numbers until the end of the question Now by applying this number to the mol ratio, we can calculate the number of moles of sodium in sodium chloride 1 mole of sodium chloride molecules : 1 mole of Chloride atoms =0.20019584971759552122529442050745 : 0.20019584971759552122529442050745 Now that we have established that the number of moles of of sodium in 11.7g of sodium chloride is 0.20019584971759552122529442050745 mol, the mass of sodium in 11.7g of sodium chloride can be calculated with the formula, m = n M = mass of sodium in 11.7g of sodium chloride = 0.20019584971759552122529442050745 X 23 = 4.6045045435046969881817716716713g (all decimal places)
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
60,33417 % chlorine and 39,66583 % sodium
The atomic ratio between sodium and chlorine in sodium chloride is 1:1, as indicated by its formula NaCl. If the mass ratio is wanted, it is that of the atomic weights of the two elements.
In sodium chloride, the ratio is 1/1.
1 mol = 1 mol
The ratio mass of chlorine/mass of sodium is 1,5.
1:1, one mole potassium to one mole chlorine
Sodium chloride has a 1 to 1 ratio of its constituent atoms, sodium and chlorine. Sodium chloride, table salt, is a two-atom molecule. One atom of sodium is bonded to one atom of chlorine. The two atoms have combine to make a molecule of salt in a one-to-one ratio.
Lite salt is a mixture 1:1 of sodium and potassium chloride.This is a mixture sodium chloride/potassium chloride in the ratio 1:1.
The number of elementary entities in a mole of the substance. The elementary entities depends on the particles making up the substance. For example, argon is made of single atoms, so a mole of argon simply contains Avogadro's number of atoms. Water, on the other hand, is made of molecules, so a mole of water contains Avogadro's number of molecules. Now each water molecule, H2O, contains 3 atoms so a mole of water contains 3xAvogadro's number of atoms. Sodium chloride, NaCl, is made of sodium and chloride ions, in a ratio of 1:1. So a mole of sodium chloride contains Avogadro's number of sodium ions, and Avogadro's number of chloride ions. A mole of sodium chloride therefore contains 2xAvogadro's number of ions in total. The number comes from the number of carbon atoms in 12g of carbon-12.