Lithium and nitrate don't react.
Only ... ... are precipitating to solid.
(SO42-)aq + (Ba2+)aq --> (BaSO4)s
The products of the reaction are solid calcium sulfate and aqueous lithium nitrate.
Ba(NO3)2aq) + Li2SO4(aq) → BaSO4(s) + 2LiNO3(aq) Apologies as I can't subscript using my mobile.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
Net Ionic: Pb2+(aq)+SO42-(aq) --> PbSO4(s) Molecular: Pb(NO3)2(aq) + K2SO4(aq) --> PbSO4(s) + 2KNO3(aq)
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
I think that there is no reaction, both of them are soluble. so they stay as the ions and cations in aqueous.
The products of the reaction are solid calcium sulfate and aqueous lithium nitrate.
Ba(NO3)2aq) + Li2SO4(aq) → BaSO4(s) + 2LiNO3(aq) Apologies as I can't subscript using my mobile.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
Net Ionic: Pb2+(aq)+SO42-(aq) --> PbSO4(s) Molecular: Pb(NO3)2(aq) + K2SO4(aq) --> PbSO4(s) + 2KNO3(aq)
FeO+LiNO3------->LiO+FeNO3it is already balanced ..............................
It would come out to Ag^+ + Cl^- = AgCl Remember solubility rules nitrate and Ca both are soluble therefore they are not in the final equation.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
Lithium Nitrate
2I- + Pb2+ ? PbI2 (s)
2Ag(NO3)2+CaCl2 ---> 2AgCl +Ca(NO3)2
It would be2 K3PO4 + 3 Co(NO3)2 = Co3(PO4)2 + 6 KNO3