Upon heating copper II nitrate, the decomposition reaction is as follows:
2 Cu(NO3)2(s) --> 4 NO2(g) + O2(g) + 2 CuO(s)
First the NO2 gas is released, as it is the larger molecule, then O2 gas, leaving CuO solid remaining.
2Cu(NO3)2(s)+heat------->2CuO(s)+4NO2(g)+O2(g)
When heat copper hydroxide and sodium Nitrate the pale blue precipitate change into black solid
The heat for this reaction is called the heat of solution for ammonium nitrate. When the reaction is finished, the system contains two substances, the calorimeter itself and the aqueous solution, and there is a heat associated with each component.
cuso4 - 5h2o= cuso4 + 5h20 + heat
2KNO3 (s) ==heat==> 2KNO2(s) + O2(g) potassium nitrate decomposes to potassium nitrite and oxygen. NB Note the spelling for the product.
The balanced equation is Cu(OH)2 (s) (heat) = CuO + H2O.
2Cu(NO3)2(s)+heat------->2CuO(s)+4NO2(g)+O2(g)
When heat copper hydroxide and sodium Nitrate the pale blue precipitate change into black solid
copper oxide, nitrogen and oxygen
Heat the liquid to boil off excess water and the copper nitrate will crystalise out of the solution as it cools. Then filter to separate the crystals from the liquid.
The heat for this reaction is called the heat of solution for ammonium nitrate. When the reaction is finished, the system contains two substances, the calorimeter itself and the aqueous solution, and there is a heat associated with each component.
Kn2 heat equal kn2+o2
If you are asking why DOES copper bend on heating, then i can answer that. When heat is applied, the copper molecules are spread farther apart, making the molecular structure weaker, thus you may bend it.
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
Cu(OH)2 => CuO + H2O.
cuso4 - 5h2o= cuso4 + 5h20 + heat
2KNO3 (s) ==heat==> 2KNO2(s) + O2(g) potassium nitrate decomposes to potassium nitrite and oxygen. NB Note the spelling for the product.