Silver Bromide
Silver (Ag) is an element.
Bromide: Ag+ + Br- = AgBr which is a cream precipitate Chloride: Ag+ + Cl- = Ag Cl which is a white precipitate Iodide: Ag+ + I- = AgI which is a yellow precipitate
Silver chloride. (The compound is ionic. No charges required, silver is almost always a +1 charge.) Hope it helps.
AgBr + Ag(NO)3 ----------> Ag+ + Br- Disregard Ag(NO)3 b/c of the common ion Ag and the fact that (NO)3 is a spectator ion. You use the Ksp of AgBr from the index in your book that equals 5.0*10^-13 If you look at your above equation, Ksp = [Ag] [Br] You know Ksp = 5.0*10^-13 You have also been given the concentration of Ag from Ag(NO)3 = 3.0*10^-2. You use this number because remember NO3 is always a spectator ion so [Ag] will equal the [Ag(NO)3] You equation should look like this. (Forget about doing the I.C.E on this one. Its not necessary. 5.0*10^-13-= [3.0*10^-2] [Br] Simply solve for [Br] by dividing 5.0*10^-13 by 3.0*10^-2. [Br] = 1.66*10^-11. Round for sig figs to = 1.7*10-11
SrBr2
The formula of a compound that contains Ag, N and O is Ag(NO3). The name of the compound is silver nitrate.
Ethylbromide is the name of the compound CH3-CH2-Br.
First, Ag is an element and not a compound at this form. Its name is silver
This is the lead tribromide.
silver bromine
Sodium Bromide
Ag, Hg, Pb
the answer is Ag Br
Magnesium Bromide
If this really is a compound, it is named "magnesium bromide hydroxide".
The compound AgN doesn't exist; the silver nitride is Ag3N.
This formula is for silver phosphide.