If molybdenum-91 undergoes beta plus decay, or positron emission, the equation will look like this: 4291Mo => 4191Nb + e+ + ve In this reaction, a proton in the nucleus of the Mo-91 atom undergoes a change mediated by the weak interaction or weak force. This involves an up quark changing into a down quark, and the proton becomes a neutron. Nuclear transmutation takes place, and the Mo-91 atom becomes an atom of niobium, Nb-91. The positron, represented by e+, and a neutrino, the ve, will be ejected from the nucleus. Links can be found below if you wish to check facts and do some additional investigating.
it is a combustion. the word equation would be: sulfur + oxygen → sulfur dioxide the balanced chemical equation: S(s) + O₂(g) → SO₂(g)
The balanced equation for the reaction between sulfur, oxygen, and water is: Sulfur + Oxygen + Water → Sulfuric Acid
Sulfur emits a pale blue light when burned, producing a blue flame.
The chemical equation for the reaction of sulfur and oxygen to form sulfur trioxide is: 2S + 3O2 -> 2SO3
The balanced chemical equation for the reaction of sulfur dioxide with water is: SO2 + H2O → H2SO3
For nuclear decay, you must also specify what isotope you are talking about. Just saying "Sulfur" simply isn't enough information.
Sulfur oxide can refer to both sulfur dioxide (SO2) and sulfur trioxide (SO3). The word equation for sulfur dioxide is sulfur + oxygen → sulfur dioxide. The word equation for sulfur trioxide is sulfur + oxygen → sulfur trioxide.
it is a combustion. the word equation would be: sulfur + oxygen → sulfur dioxide the balanced chemical equation: S(s) + O₂(g) → SO₂(g)
35S --> 35Cl + e- 35Cl, stable
The word equation for sulfur when it burns is: sulfur + oxygen → sulfur dioxide.
SO2: sulfur dioxide S + O2 --> SO2
The word equation for the combustion of sulfur is sulfur + oxygen → sulfur dioxide.
The word equation for the reaction between sulfur and air is: sulfur + oxygen → sulfur dioxide.
The equation for the burning of sulfur in the presence of oxygen to produce sulfur dioxide is: S (sulfur) + O2 (oxygen) --> SO2 (sulfur dioxide).
The balanced equation for the reaction between sulfur, oxygen, and water is: Sulfur + Oxygen + Water → Sulfuric Acid
Sulfur emits a pale blue light when burned, producing a blue flame.
The equation for the formation of sulfur dioxide in an engine is SO2 = S + O2. When sulfur-containing fuel (such as diesel containing sulfur) is burned in the engine, sulfur reacts with oxygen in the air to form sulfur dioxide.