301.8g H2O
There are four molecules of water in 4H2O. One molecule of water is written as H2O. The subscript 2 tells you that there are two H(hydrogen) atoms. Since there is no subscript after the O there is one O(oxygen) atom. Now back to 4H2O. The coefficient 4 tells you there are four molecules of H2O. Therefore there are eight H(hydrogen) atoms and four O(oxygen) atoms.
im not really sure but here is what i think it is: 0.943 mole H2Ox 6.02x10^23 molecules H2O= 5.67686^23 molecules H2O sorry if its wrong.
1.08x10^22
No, H2O does not have a possible resonance structures.
Since the molar mass (grams per mole) of H2O is 18.02, the grams of H2O in 4 moles is 72.08g.
The number of molecules is 2,308.10e23.
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
200 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O) = 6.69 X 1024 molecules of water ======================
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O=18.0 grams235 grams H2O / (18.0 grams) = 13.1 moles H2O
There are four molecules of water in 4H2O. One molecule of water is written as H2O. The subscript 2 tells you that there are two H(hydrogen) atoms. Since there is no subscript after the O there is one O(oxygen) atom. Now back to 4H2O. The coefficient 4 tells you there are four molecules of H2O. Therefore there are eight H(hydrogen) atoms and four O(oxygen) atoms.
Formula mass / Formula weight / Molecular mass / Molecular weight of H2O = (1*2) + 16 = 18g 1 mol of H2O = 18g H2O 1 mol of H2O = 6.023 * 10^23 molecules In 18g H2O there are 6.023 * 10^23 molecules. So, In 1g H2O there are (6.023 * 10^23) / 18 molecules = 3.346 * 10^22 molecules Therefore, In 7.3g H2O there are (3.346 * 10^22) * 7.3 molecules = 2.443 * 10^23 molecules Ans: 2.443 * 10^23 molecules
6 grams water (1 mole H2O/18.016 grams)(6.022 X 10^23/1 mole H2O) = 2.0 X 10^23 molecules of water
The molar mass of H2O =(2 atoms H x 1.00794g/mol H) + (1 atom O x 15.9994g/mol O) = 18.0152g/mol H2O1 mole of H2O = 18.0152g H2O1 mole of H2O molecules = 6.022 x 1023 molecules H2OConvert molecules to moles.5.00 x 102g H2O molecules x (1mole H2O/6.022 x 1023 molecules H2O) =8.31 x 10-22 mole H2OConvert moles to grams.8.31 x 10-22 mole H2O x (18.0152g H2O/1mole H2O) = 1.50 x 10-20g H2OAnswer: The mass in grams of 5.00 x 102g H2O molecules = 1.50 x 10-20g H2O
18 grams
95.2 grams water (1 mole H2O/18.016 grams)(6.022 X 10^23/1 mole H2O) = 3.18 X 10^24 molecules of water
The mass is 74,7 mg.
Avogadro's Number is defined as the number of molecules in one gram atomic molecular mass of a substance and is known to have the approximate value of 6.022 X 1023. The gram molecular mass of water, with formula H2O, is 18.01528. Therefore, the number of water molecules in 1.805 grams of water is: (1.805/18.01528)(6.022)(1023) or 6.034 X 1022 molecules, to the justified number of significant digits.