This answer is -1.
To find this answer:
Oxygen has an oxidation number of -2.
Hydrogen has an oxidation number of +1, and there are 3 of them
you want to get the oxidation numbers to add up to 0, so it would be neutral.
-2 + 3(+1) = +1
Now, to get this to equal zero, it means that N has to be -1.
This answer is -1.To find this answer:Oxygen has an oxidation number of -2.Hydrogen has an oxidation number of +1, and there are 3 of themyou want to get the oxidation numbers to add up to 0, so it would be neutral.-2 + 3(+1) = +1Now, to get this to equal zero, it means that N has to be -1.
Nitrogen can exist in oxidation states ranging from -3 to +5. Some common nitrogen compounds with different oxidation states include ammonia (NH3) in the -3 oxidation state, nitric oxide (NO) in the +2 oxidation state, nitrogen dioxide (NO2) in the +4 oxidation state, and nitric acid (HNO3) in the +5 oxidation state.
The oxidation state of nitrogen in LiNO3 is +5. This is because the sum of the oxidation states of all atoms in the compound must equal the charge of the compound, and lithium is always +1 and oxygen is always -2.
The oxidation state of nitrogen in HNO3 is +5 because oxygen is assigned an oxidation state of -2 and hydrogen is assigned an oxidation state of +1. The sum of the oxidation states must equal the overall charge of the molecule (zero in this case for a neutral compound).
The oxidation state of nitrogen in NaNO2 is +3. This is because sodium is typically in the +1 oxidation state, and oxygen is in the -2 oxidation state. By assigning x to the oxidation state of nitrogen, the sum of the oxidation states in NaNO2 equals zero. Solving for x gives nitrogen an oxidation state of +3.
This answer is -1.To find this answer:Oxygen has an oxidation number of -2.Hydrogen has an oxidation number of +1, and there are 3 of themyou want to get the oxidation numbers to add up to 0, so it would be neutral.-2 + 3(+1) = +1Now, to get this to equal zero, it means that N has to be -1.
Nitrogen can exist in oxidation states ranging from -3 to +5. Some common nitrogen compounds with different oxidation states include ammonia (NH3) in the -3 oxidation state, nitric oxide (NO) in the +2 oxidation state, nitrogen dioxide (NO2) in the +4 oxidation state, and nitric acid (HNO3) in the +5 oxidation state.
The oxidation number of N in NH2OH is -1. This is because each hydrogen atom has an oxidation number of +1, and oxygen usually has an oxidation number of -2. Since the overall molecule has a neutral charge, nitrogen must have an oxidation number of -1 to balance out the charges.
In NH4F, nitrogen has an oxidation state of -3, hydrogen has an oxidation state of +1, and fluorine has an oxidation state of -1.
the oxidation number of nitrogen is 5
The oxidation state of NO is +1. This is because nitrogen is in Group 15 of the periodic table and typically has an oxidation state of -3. In NO, oxygen is more electronegative than nitrogen, causing nitrogen to have a formal oxidation state of +1 to balance the charge.
In KNO3, the nitrogen atom has an oxidation state of +5. This is because potassium (K) is in Group 1 and has an oxidation state of +1, and oxygen (O) is in Group 6 and has an oxidation state of -2. To balance the charges, nitrogen must have an oxidation state of +5.
NH2OH is a covalent compound. It contains covalent bonds formed between nitrogen and hydrogen atoms.
The oxidation state of nitrogen in NH4+ is -3.
-3
The oxidation state of nitrogen (N) in NH4+ is -3. Nitrogen usually has a -3 oxidation state in ammonium ion (NH4+) as hydrogen is typically considered to have +1 oxidation state and there are four hydrogen atoms bonded to nitrogen in NH4+.
In NH3 the oxidation state of Nitrogen is -3. It has 3 extra electrons in three polar covalent bonds, 'donated' from three bonded hydrogen atoms. Hydrogen has an oxidation state of +1 in this compound.