Molarity = moles of solute/liters of solution
M = 10 mol NaOH/1 liter
= 10 M
-log(10 M)
= -1
14 - (-1)
= 15 pH sodium hydroxide
5 M NaOH = 5 mol/L NaOH. 1 mol of NaOH = 40 g NaOH. You can get the number of grams by multiplying 5 mol/L and 40g/mol. This will give you 200g/L. Just multiply by the volume, which is 1 Liter, and you will get 200 g of NaOH.
the molar mass of sodium hydroxide is 40g/mol mike
To find the grams of sodium hydroxide in 0.150 mol, first calculate the molar mass of sodium hydroxide, which is approximately 40 g/mol. Then, multiply the molar mass by the number of moles: 40 g/mol x 0.150 mol = 6 grams of sodium hydroxide.
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
To find the grams of sodium hydroxide needed, you first calculate the moles required using the molarity equation (moles = Molarity x Volume). Then, convert moles to grams using the molar mass of sodium hydroxide, which is 40 g/mol. Finally, the calculation would be: (7.80 mol/L) x 0.250 L x 40 g/mol = 78 grams of sodium hydroxide.
5 M NaOH = 5 mol/L NaOH. 1 mol of NaOH = 40 g NaOH. You can get the number of grams by multiplying 5 mol/L and 40g/mol. This will give you 200g/L. Just multiply by the volume, which is 1 Liter, and you will get 200 g of NaOH.
No, they are not. "0.5 mole of NaOH" means that you have half a mole of sodium hydroxide. "0.5M of NaOH" means that you have half a mole of sodium hydroxide for every liter of solution. "0.5M" is also commonly written as "0.5 mol/L" or "mol L-1".
To determine the mass of sodium hydroxide used in preparing a 2M solution, you need to know the volume of the solution you are preparing. The concentration of 2M means there are 2 moles of sodium hydroxide in 1 liter of solution. You can use the formula: mass = molarity x volume x molar mass to calculate the mass of sodium hydroxide. For example, if you are preparing 1 liter of the solution, the mass would be 2 x 1 x 40 g/mol (molar mass of NaOH) = 80 grams.
To make a 0.25 mol solution of sodium nitrite, measure out 8.25 grams of sodium nitrite (NaNO2) (sodium nitrite has a molar mass of 69.01 g/mol) and dissolve it in enough water to make a total volume of 1 liter. This will give you a 0.25 mol/L solution of sodium nitrite.
the molar mass of sodium hydroxide is 40g/mol mike
To find the grams of sodium hydroxide in 0.150 mol, first calculate the molar mass of sodium hydroxide, which is approximately 40 g/mol. Then, multiply the molar mass by the number of moles: 40 g/mol x 0.150 mol = 6 grams of sodium hydroxide.
To determine the number of moles in 20g of sodium hydroxide, you need to divide the given mass by the molar mass of sodium hydroxide. The molar mass of NaOH is 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). So, 20g NaOH / 40 g/mol = 0.5 moles of sodium hydroxide.
6N NaOH refers to a solution of sodium hydroxide (NaOH) that has a concentration of 6 normal (6N) strength. This means that the solution contains a high concentration of NaOH, which is a strong base commonly used in laboratory settings for various chemical reactions.
The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of hydroxide (OH) is 17.01 g/mol. To find the molar mass of sodium hydroxide (NaOH), you can add the molar masses of sodium and hydroxide together, which equals 39.00 g/mol.
You would need 1.25 moles of ammonium hydroxide to make one liter of a 1.25 mol/L solution.
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
The moles of sodium hydroxide can be calculated as 0.500 mol/L * 0.0148 L = 0.0074 mol. Since the reaction is 1:1 between HCl and NaOH, the moles of HCl in 35.00 ml is also 0.0074 mol. Therefore, the concentration of HCl is 0.0074 mol / 0.035 L = 0.211 mol/L.