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Ba = 137.327
Cr = 51.9961
O = 15.9994

BaCrO4 = 137.327 + 51.9961 + 4(15.9994) =
253.3207 g/mol

51.9961 / 253.3207 = 0.20526

0.20526 x 100 = 20.526

The answer is:
20.526%

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20.5%

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Q: What is the percent composition composition of chromium in BaCrO4?
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Ba = 137.327 Cr = 51.9961 O = 15.9994 BaCrO4 = 137.327 + 51.9961 + 4(15.9994) = 253.3207 g/mol 51.9961 / 253.3207 = 0.20526 0.20526 x 100 = 20.526 The answer is: 20.526%