Ba = 137.327
Cr = 51.9961
O = 15.9994
BaCrO4 = 137.327 + 51.9961 + 4(15.9994) =
253.3207 g/mol
51.9961 / 253.3207 = 0.20526
0.20526 x 100 = 20.526
The answer is:
20.526%
20.5%
The percent composition of lithium in LiOH is: 29,21 %.
Can you be more specific? Percent composition is usually the percent of an element in a compound.
The percent composition of ethanol is: - C: 52,13 % - O: 34,74 % - H: 13,13 %
The percent composition of manganese dichoride (MnCl2) is: - Mn: 44 % - Cl: 56 %
Chromium form three (not only two) bromides: * CrBr2, containing 24,759 85 % chromium * CrBr3, containing 17,991 45 % chromium * CrBr4, containing 14,129 09 % chromium 1 gram of CrBr3 contain 179,91 45 mg chromium.
Barium = Ba2+Chromate = CrO4-2So the formula of Barium chromate is BaCrO4.
Cr3Si2 is the empirical formula for a compound containing chromium and silicon an has 73.52 mass percent chromium.
Ruby is aluminium oxide; chromium is only a natural dopant, in traces. The concentration of chromium is not constant in rubies.
Chromium: 16-18,5 % Nickel: 10-14 % For details see the link below.
Ruby is aluminium oxide (Al2O3) with chromium as an impurity.
The percent composition of lithium in LiOH is: 29,21 %.
Can you be more specific? Percent composition is usually the percent of an element in a compound.
Percent composition is usually expressed as a percent by mass, but in the case of gases and vapors, it is often expressed as a percent by volume.
Formula: BaCrO4
The continent of Africa is home to 12 percent of the world's oil reserves, 40 percent of its gold, and around 85 percent of its chromium and platinum.
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
Ba = 137.327 Cr = 51.9961 O = 15.9994 BaCrO4 = 137.327 + 51.9961 + 4(15.9994) = 253.3207 g/mol 51.9961 / 253.3207 = 0.20526 0.20526 x 100 = 20.526 The answer is: 20.526%