The percent composition of ethanol is:
- C: 52,13 %
- O: 34,74 %
- H: 13,13 %
The structural formula CH3CH2OH describes ETHANOL.
The percent composition for CuBr2 is: Cu= 28.45% Br= 71.55%
MnCl2 contains one manganese (Mn) atom and two chlorine (Cl) atoms. To calculate the percent composition, divide the molar mass of each element by the molar mass of the compound and multiply by 100. The percent composition of Mn in MnCl2 is 25.41%, and the percent composition of Cl is 74.59%.
The formula of the compound between calcium and sulfur with the given percent composition would be CaS. This is because the ratio of calcium to sulfur atoms in calcium sulfide matches the given percentage composition.
The formula of water is H2O. The gram atomic mass of hydrogen is 1.008 and the gram atomic mass of oxygen is 15.999. Therefore, the mass percent composition of hydrogen in water is 100{(2)(1.008)/[(2)(1.008) + 15.999] or 11.19 %.The percent composition of hydrogen in water is: 11,19 %.
To calculate the percent carbon in ethanol (CH3CH2OH), you can sum the atomic masses of the carbon atoms and divide by the molecular weight of the compound. In ethanol, there are two carbon atoms. The percent carbon can be calculated as (2 * 12.01 g/mol / 46.08 g/mol) * 100% = 52.08% carbon.
The percent composition of lithium in lithium bromide (LiBr) is approximately 7.7%. The percent composition of bromine in lithium bromide is approximately 92.3%.
The percent composition of C5H12 is: carbon (C) = 83.78%, hydrogen (H) = 16.22%.
The condensed structural formula for ethanol is CH3CH2OH.
The structural formula CH3CH2OH describes ETHANOL.
To find the percent composition, first calculate the total mass by adding the masses of Argon and Sulfur. Then, determine the percent composition of each element by dividing the mass of that element by the total mass and multiplying by 100. In this case, the percent composition of Argon is about 87.1%, and the percent composition of Sulfur is about 12.9%.
To find the percent composition of each element in the compound, you first calculate the molar mass of Be (9.01 g/mol) and I (126.90 g/mol). Then, calculate the percent composition of each element by dividing the mass of the element by the total molar mass of the compound and multiplying by 100. The percent composition of Be is 5.14% and the percent composition of I is 94.86%.
The percent composition of Cr2O3 is approximately 68% Chromium (Cr) and 32% Oxygen (O).
The percent composition of calcium fluoride is approximately 51.1% calcium and 48.9% fluorine.
Sodium bromide has a percent composition of approximately 22.8% sodium and 77.2% bromine.
The percent composition for CuBr2 is: Cu= 28.45% Br= 71.55%
MnCl2 contains one manganese (Mn) atom and two chlorine (Cl) atoms. To calculate the percent composition, divide the molar mass of each element by the molar mass of the compound and multiply by 100. The percent composition of Mn in MnCl2 is 25.41%, and the percent composition of Cl is 74.59%.