Carbonic acid - H2CO3
Find the atomic masses of each element and multiply it by however many atoms are in the compound, then add them together.
H = 1.007 × 2 = 2.014
C = 12.01
O = 16.00 × 3= 48.00
Molecular mass = 2.014 + 12.01 + 48.00 = 62.02 grams/mole
Take the mass of a specific element (above) and divide it by the total molecular mass. Change the final answer to a percent
Hydrogen: 2.014 ÷ 62.02 = .0325 = 3.25%
Carbon: 12.01 ÷ 62.02 = .194 = 19.4%
Oxygen: 48.00 ÷ 62.02 = .774 = 77.4%
Carbonic acid contains 3.25% Hydrogen, 19.4% Carbon, and 77.4% Oxygen.
The percent composition for CuBr2 is: Cu= 28.45% Br= 71.55%
MnCl2 contains one manganese (Mn) atom and two chlorine (Cl) atoms. To calculate the percent composition, divide the molar mass of each element by the molar mass of the compound and multiply by 100. The percent composition of Mn in MnCl2 is 25.41%, and the percent composition of Cl is 74.59%.
The formula of the compound between calcium and sulfur with the given percent composition would be CaS. This is because the ratio of calcium to sulfur atoms in calcium sulfide matches the given percentage composition.
The formula of water is H2O. The gram atomic mass of hydrogen is 1.008 and the gram atomic mass of oxygen is 15.999. Therefore, the mass percent composition of hydrogen in water is 100{(2)(1.008)/[(2)(1.008) + 15.999] or 11.19 %.The percent composition of hydrogen in water is: 11,19 %.
Ammonium carbonate has the formula (NH4)2CO3. To calculate the percent composition, you first find the molar mass of each element and then divide the molar mass of each element in the formula by the formula mass of the compound and multiply by 100 to get the percentage.
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
The composition of air expired is approximately 16% oxygen (O2) and 4% carbon dioxide (CO2), with the remaining 80% being nitrogen (N2) and trace gases.
your face it it co2
The percent composition of lithium in lithium bromide (LiBr) is approximately 7.7%. The percent composition of bromine in lithium bromide is approximately 92.3%.
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-- Take the number of percent. -- Multiply it by 10,000-- The answer is the number of parts per million. . 10 percent = 100,000 parts per million.
The percent composition of C5H12 is: carbon (C) = 83.78%, hydrogen (H) = 16.22%.
To find the percent composition of each element in the compound, you first calculate the molar mass of Be (9.01 g/mol) and I (126.90 g/mol). Then, calculate the percent composition of each element by dividing the mass of the element by the total molar mass of the compound and multiplying by 100. The percent composition of Be is 5.14% and the percent composition of I is 94.86%.
To find the percent composition, first calculate the total mass by adding the masses of Argon and Sulfur. Then, determine the percent composition of each element by dividing the mass of that element by the total mass and multiplying by 100. In this case, the percent composition of Argon is about 87.1%, and the percent composition of Sulfur is about 12.9%.
The percent composition of calcium fluoride is approximately 51.1% calcium and 48.9% fluorine.
Sodium bromide has a percent composition of approximately 22.8% sodium and 77.2% bromine.