The formula unit for ammonium sulfide is (NH3)2S. There are 2 nitrogen atoms, 6 hydrogen atoms, and 1 sulfur atom per formula unit. Its molar mass is 66.12g/mol.
Mass of Nitrogen = 14.007g/mol x 2 = 28.014g/mol
Percent Composition of Nitrogen = (28.014g/mol)/(66.12g/mol) x 100 = 42.37%
Mass of Hydrogen = 1.008g/mol x 6 = 6.048g/mol
Percent Composition of Hydrogen = (6.048g/mol)/(66.12g/mol) x 100 = 9.147%
Mass of Sulfur = 32.06g/mol
Percent Composition of Sulfur = (32.06g/mol)/(66.12g/mol) x 100 = 48.49%
42.37% + 9.147% + 48.49% = 100.00%
The formula for ammonium sulfide is (NH4)2S.
Diammonium sulfide
Calcium Sulfide(main product) and Ammonium Bromide(bi-product)
Ammonium sulfide is a salt, formed from the reaction between ammonia and hydrogen sulfide. It dissociates in water to produce ammonium ions and sulfide ions. It is commonly used as a reagent in chemical reactions.
The chemical formula for ammonium sulfide is (NH4)2S. It is a compound formed by the combination of ammonium ion (NH4+) and sulfide ion (S2-).
The chemical formula of ammonium sulfide is NH4S.
The formula for ammonium sulfide is (NH4)2S.
The formula for ammonium sulfide is (NH4)2S.
The correct chemical name for (NH4)2S is ammonium sulfide.
Yes, ammonium sulfide is an ionic compound. It is composed of the ammonium ion (NH4+) and the sulfide ion (S2-), which are held together by ionic bonds formed through the transfer of electrons from the ammonium ion to the sulfide ion.
There are 3.24 x 10^24 hydrogen atoms in 2.70 moles of ammonium sulfide. This is calculated by multiplying the number of moles of ammonium sulfide by the number of hydrogen atoms in one molecule of ammonium sulfide (4).
Diammonium sulfide
The compound (NH4)2S is ammonium sulfide.
Calcium Sulfide(main product) and Ammonium Bromide(bi-product)
Ammonium sulfide is a salt, formed from the reaction between ammonia and hydrogen sulfide. It dissociates in water to produce ammonium ions and sulfide ions. It is commonly used as a reagent in chemical reactions.
there are 1.30e25 Hydrogen atoms in 2.70 mol Ammonium Sulfide
It is important to know that the percent of nitrogen in 4.444 moles of ammonium sulfide is the same as the percent of nitrogen in 454 grams or 4843 moles or 96 kg, etc. Remember the law of definite proportions - chemical compounds always contain the same proportion of elements by mass. Perhaps you were asking how much nitrogen is in 4.444 moles of ammonium sulfide given the percent of nitrogen in any given mass. So we'll do that too: find the percent of nitrogen in any given sample and apply it specifically to 4.444 moles.Before we go directly to the 4.444 moles, we have to figure out how much nitrogen is in any amount of ammonium sulfide by percent. To do this, we need the atomic weights of the elements and add them up to find the total molar mass of the compound.Ammonium sulfide = (NH4)2SNitrogen = 14.0 grams × 2 = 28.0 gramsHydrogen = 1.01 grams × 8 = 8.08 gramsSulfur = 32.1 grams------------------------------------------------------Ammonium sulfide = 68.2 gramsNow we take the mass of nitrogen and divide it by the total mass to get our percent.Nitrogen ÷ Ammonium sulfide = % Nitrogen28.0 grams ÷ 68.2 grams = 0.411 = 41.1% Nitrogen in Ammonium sulfideSince we know that in any amount of Ammonium sulfide contains 41.1% of Nitrogen, we can apply it to the mass given.41.1% of 4.444 moles = .411 × 4.444 = 1.83 moles of Nitrogen in 4.444 moles Ammonium sulfide