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What is the maximum mass of aluminum chloride that can be formed when reacting 22.0 of aluminum with 27.0 of chlorine?
This equation shows how much AlCl3 can be produced with 22.0g of Al. 22.0g Al x (1 mol Al/26.98g) x (2 mol AlCl3/2mol Al) x (133.34 g/1 mol AlCl3) = 108.66g AlCl3 This equation shows how much AlCl3 can be produced with 27.0g of Cl2. 27.0g Cl2 x (1 mol Cl2/70.91g) x (2mol AlCl3/3 mol Cl2) x (133.34g/1 mol AlCl3) = 33.87g AlCl3 This shows that chlorine is the limiting reactant. Only 33.87 grams of AlCl3 can be produced before the chlorine will run out. Using significant figures, the answer is 33.8g of AlCl3
How many atoms are in AlCL3?
The number of atoms in AlCl3 will vary depending on how much AlCl3 you have. If you have one single molecule (formula unit) of AlCl3, then there are 4 atoms. If you have 10 molecules (formula units) then there are 40 atoms, and so on.
Is Al Cl formula correct?
AlCl3 is the correct formula as the valency of aluminium and chlorine are 3 and 1 respectively.
1. The ionic compound made from aluminum and chlorine has the formula AlCl3. Explain in detail why it is the correct formula?
ionic bonding
What is the chemical formula for Aluminum Chlorine?
(inorganic chemistry) AlCl3 or Al2Cl6 A deliquescent compound in the form of white to colorless hexagonal crystals; fumes in air and reacts explosively with water; used as a catalyst
What is the aluminum and chlorine formula?
AlCl3
How many atoms of chlorine are in aluminum chloride?
There are 3 atoms of chlorine in aluminum chloride (AlCl3).
What is produced from aluminium and chlorine?
This compound is aluminium chloride - AlCl3.
What is the ionic compound of aluminum and chlorine?
The ionic compound formed between aluminum and chlorine is aluminum chloride (AlCl3). In this compound, aluminum donates three electrons to each chlorine atom to form a stable ionic bond.
Is AlCl3 a covalent or ionic compound?
Solid AlCl3 is ionic. Liquid and gaseous AlCl3 is present as a covalent dimer, Al2Cl6. At high temperatures the dimer dissociates to form the planar covalent monomer AlCl3.
How many chlorine atoms are on the products side of the reaction 2Al 6HCl 2AlCl3 3H2?
There are 6 chlorine atoms on the products side of the reaction, in the form of 2 molecules of AlCl3. Each molecule of AlCl3 contains 3 chlorine atoms.
What is the oxidation number of chlorine in AlCl 3?
The oxidation number of chlorine in AlCl3 is -1. This is because aluminum has a +3 oxidation state in this compound, and the overall charge of AlCl3 is neutral, so the chlorine atoms must have an oxidation state of -1 to balance the charge.
What is the atomic breakdown of Aluminium chloride?
Aluminium chloride (AlCl3) has one aluminium atom (Al) and three chlorine atoms (Cl). The chemical formula AlCl3 indicates that there is one aluminium atom bonded to three chlorine atoms in the compound.
What is the valency of AlCl3?
The valency of AlCl3 is 3. This is because aluminium (Al) has a valency of +3 and each chlorine atom (Cl) has a valency of -1, so it takes 3 chlorine atoms to balance the charge of one aluminium atom.
Is alcl3 a direct combination?
Yes, AlCl3 (aluminum chloride) is formed through a direct combination reaction between aluminum metal and chlorine gas.
How do you work up Alcl3 without using water?
Aluminum chloride (AlCl3) can be generated by reacting aluminum metal with chlorine gas in a fume hood to avoid exposure to chlorine gas. The resulting solid can then be purified by sublimation under vacuum to remove any impurities. Alternatively, anhydrous AlCl3 can be purchased from chemical suppliers if the creation of AlCl3 in-house is not suitable.
What is the maximum mass of aluminum chloride that can be formed when reacting 22.0 of aluminum with 27.0 of chlorine?
This equation shows how much AlCl3 can be produced with 22.0g of Al. 22.0g Al x (1 mol Al/26.98g) x (2 mol AlCl3/2mol Al) x (133.34 g/1 mol AlCl3) = 108.66g AlCl3 This equation shows how much AlCl3 can be produced with 27.0g of Cl2. 27.0g Cl2 x (1 mol Cl2/70.91g) x (2mol AlCl3/3 mol Cl2) x (133.34g/1 mol AlCl3) = 33.87g AlCl3 This shows that chlorine is the limiting reactant. Only 33.87 grams of AlCl3 can be produced before the chlorine will run out. Using significant figures, the answer is 33.8g of AlCl3
