What is the percent sodium in sodium oxide?

Answer 1

Since quantity is not mentioned, we take on mole of Sodium Carbonate.

One mole of Sodium Carbonate=106g

One mole of Na2CO3 has 3 moles of oxygen which are equal to 48g

Mass% of oxygen = 48/106 * 100 =45.28%

Answer 2

Sodium oxide (Na₂O) contains two sodium atoms and one oxygen atom. The percent sodium in sodium oxide is calculated as the mass of sodium divided by the total mass of the compound, multiplied by 100. Sodium's Atomic Mass is 22.99 g/mol and oxygen's atomic mass is 16.00 g/mol. Therefore, the percent sodium in sodium oxide is around 71.6%.

Answer 3

sodium carbonate is Na2CO3 Na has an atomic mass of 23, C is 12, and O is 16. That gives it a total Mass of 106, 46 of that being Na. That makes it 43.4% Sodium.

Answer 4

Na2O - Sodium Oxide

Via moles - 33.3333....% Sodium

By mass ~ 74.2% Sodium

Oxygen 15.999 g/mol

Sodium 22.990 g/mol

Na2O 61.979 g/mol

Answer 5

Na = 23
H = 1C = 12

O = 16 x 3 = 48

Total = 23 + 1 + 12 + 48 = 84

%Na = 23/84 (x100%) = 27.4%

Answer 6

100/1 x 208/284 = 73.2394366%