The microbicidal effectiveness of pharmaceutical iodophor preparations comprising an organic substance which reacts with iodine to form a complex thereof, such as polyvinylpyrrolidone, iodine bound thereto in complex form, free iodine, and iodide ions, is assured by controlling the ratio of total iodine (complex bound iodine and free iodine) to iodide ions at between 2:1 and 10:1, this ratio being adjusted without chemical oxidizing agents such as iodate ions by anodic oxidation of a solution of the iodophor preparation and iodide ions. The resulting preparation can be free of chemical oxidizing ions such as iodate ions
Lugol's Iodine = 20g Potassium Iodide + 10g Iodine dissolved in 1L H2O Gram's Iodine = 6.7g potassium iodide + 3.3g Iodine dissolved in 1L H2O Recipe's taken from Flinn Scientific Catalog I have on campus. Looks to me as Gram's is just a dilute version of Lugol's. Same ratio of KI:I just less of it. Couldn't tell you much about differences in application however.
Preparation of iodine monochloride entails simply combining the halogens in a 1:1 molar ratio, according to the equation :- I2 + Cl2 → 2 ICl (iodine) + (chlorine) → (iodine monochloride)
The chemical formula of potassium iodide is KI The molecule contain 1 potassium atom, 1 iodine atom; the ratio is 1.
2.m2c
blow ratio is the ratio of mold diameter to the preform diameter.
Magnesium : Iodine = 1:2
It does so in 1:3 ratio; hence the formula AlI3.Aluminum iodine is another example of iodine
The balanced equation for the reaction between Iodine and Hydrogen is: H2 + I2 --> 2HI The ratio of I2 to HI is 1:2 Therefore 1 mole of Iodine can form a maximum of 2 moles of Hydrogen Iodide
Lugol's Iodine = 20g Potassium Iodide + 10g Iodine dissolved in 1L H2O Gram's Iodine = 6.7g potassium iodide + 3.3g Iodine dissolved in 1L H2O Recipe's taken from Flinn Scientific Catalog I have on campus. Looks to me as Gram's is just a dilute version of Lugol's. Same ratio of KI:I just less of it. Couldn't tell you much about differences in application however.
== Potassium (K) and iodine (I) combine in a one-to-one ratio to form potassium iodide, which has KI as its chemical or molecular formula. A link can be found below for more information.
there is a one-to-one ratio of potassium ions to iodide ions
one-to-one ratio
one-to-one ratio
Not enough information is given. Sulfur and iodine are both non-metals and can potentially bond in more than one ratio, so you need some prefixes to accurately name these covalently bonded compounds. (see covalent bond nomenclature.)
16.296 grams. Just multiply both sides of the ORIGINAL ratio by 4.2
Preparation of iodine monochloride entails simply combining the halogens in a 1:1 molar ratio, according to the equation :- I2 + Cl2 → 2 ICl (iodine) + (chlorine) → (iodine monochloride)
There is one-one ratio of potassium ions to iodide ions.