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The formula of ammonium sulphate is (NH4)2SO4, showing that each formula mass contains one sulphur atom. The formula mass of ammonium sulphate is 132.13, and the gram atomic mass of sulphur is 32.06. Therefore, the percent by mass of sulphur in ammonium sulphate is 100(32.06/132.13) or 24.26, to the justified number of significant digits.
46.068g
If 85.65g of iron forms 118.37g of the oxide, the mass of oxygen combined with this mass of iron is 32.72g. Calculate the number of moles of iron and oxygen which have combined (after all, the formula of a compound shows the ratio of the number of moles of each element combined). Do this by dividing the mass reacted by the Relative Atomic Mass of the element concerned. i.e. For Iron it is 85.65/55.8 and for Oxygen 32.72/16. This gives a mole ratio of Fe:O as 1.53:2.04 or 3:4 Therefore the formula is Fe3O4
The anhydrous copper sulfate (CuSO4) has a molar mass of 159,62.
In one mole of each element there is... Fe - 56g O - 16g S - 32g Th equation is Fe2(SO4)3 56g x 2 = 112g 32g x 3 = 96g 16g x 12 = 192g 112g + 96g + 192g = 400g 400g
relative formula mass of MgCO3
The formula of ammonium sulphate is (NH4)2SO4, showing that each formula mass contains one sulphur atom. The formula mass of ammonium sulphate is 132.13, and the gram atomic mass of sulphur is 32.06. Therefore, the percent by mass of sulphur in ammonium sulphate is 100(32.06/132.13) or 24.26, to the justified number of significant digits.
Iron sulphate is a compound because it contains more than one element (three in this instance) in fixed ratios by mass to one another. There are at least two kinds of iron sulphate, those of iron(II) and iron(III). These have the same mass ratio between sulfur and oxygen, but the ratios of these two elements to iron are different in these two compounds.
it is because iron is solid and can easily sublimes in aqueous copper sulphate
The molar mass of Fe2(SO4)3 is 399,88 g (anhydrous).
The relative formula mass of a molecule of hydrgoen is two (2 x 1).
46.068g
The chemical formula of potassium dichromate is K2Cr2O7; and the molecular mass is 294,185.
The chemical formula is (NO3)-; the mass is 62 g.
3.2g ..... assuming it is iron (II) Sulphide FeS2. The relative atomic mass of iron is 56, sulphur is 32, so the ratio of masses of these two elements IN THE FORMULA = 56 : 64. If 2.8g of iron was used then, from the ratio, this will react with 3.2g of sulphur.
If 85.65g of iron forms 118.37g of the oxide, the mass of oxygen combined with this mass of iron is 32.72g. Calculate the number of moles of iron and oxygen which have combined (after all, the formula of a compound shows the ratio of the number of moles of each element combined). Do this by dividing the mass reacted by the Relative Atomic Mass of the element concerned. i.e. For Iron it is 85.65/55.8 and for Oxygen 32.72/16. This gives a mole ratio of Fe:O as 1.53:2.04 or 3:4 Therefore the formula is Fe3O4
The anhydrous copper sulfate (CuSO4) has a molar mass of 159,62.