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We need to find R equivalent at first then divide V from it to find the total current.
Case 1: If resistances are connected in series.
Then, R(eq.) = R1 + R2 = 500 + 1500 = 2000 ohm
So, Total current, I = V/R(eq.) = 10/2000 = 1/200 or 0.002 A.
Case 2: If resistances are connected in parallel.
Then, R(eq.) = (R1 x R2)/(R1 + R2) = (500 x 1500)/(500 + 1500) = 400 ohm
So, Total current, I = V/R(eq.) = 10/400 = 1/40 or 0.025 A.
What else can I help you with?
What is the ratio of potential difference to the current of a circuit?
The ratio of potential difference to current in a circuit is known as resistance, measured in ohms (Ω). This relationship is described by Ohm's Law, which states that resistance equals voltage divided by current (R = V/I).
How many amps are in 1500 watts?
To calculate the amperage for a given wattage, you would need to know the voltage. However, assuming a standard voltage of 120V in a household circuit, you can use the formula: Amps = Watts / Volts. For 1500 watts at 120 volts, the amperage would be 12.5 amps.
In a series RL circuit Et equals 120 volts R equals 30 ohms and XL equals 40 ohms what is the apparent power?
The apparent power (VA) is a quantity which applies to alternating current with a reactive component. It does not apply to DC and, with AC, the apparent power and real power are the same if there is only resistance present. With AC, other than just resistance there can be capacitors or inductors (coils) present. Perfect examples of these types of components do not dissipate power but do conduct current if AC voltage is applied. In your example, the resistive component is 30 ohms while the reactive impedance is 40 ohms meaning the total impedance is 50 ohms (Pythagoras). You can't just add reactance and impedance. The current through the circuit will therefore be 2.4 amps (I=V/R OR 120/50). The real or true power will be 172.8 watts ( I2 x R OR 2.42 x 30) while the apparent power will be 288 VA (2.42 x 50).
What happens to the current in a secondary that has twice as many loops as the primary?
The current in the secondary winding of a transformer is not determined by the current flowing in the primary winding; rather, it is the other way around.The current flowing through the secondary winding of a transformer is determined by the load to which it is connected. The primary current can then be determined from the turns ratio.
What is the resistance of a domestic filament lamp?
Voltage squared equals current times resistance, so voltage squared divided by power equals resistance. So, for a 60W bulb: * (120V)^2 / 60 = R * 14400 / 60 = 240 ohms Keep in mind this is after the bulb reaches operating temperature. The resistance of the filament is temperature dependent.
What do you need for a simple circuit?
volts current ohms
If the voltage is 5 volts and resistance is 25 ohms what is the current flow?
0.2 volts
How do you work out the current?
There are three formulas that you can use. Amps = Volts/Ohms Amps = Watts/Volts Amps = sq root of Watts/Ohms
If you have flow of electricity which is 5 volts and 2.6k ohms what is the current?
I = V/R 5 volts / 2600 ohms = .00192 or round to .002.
What effect are there when resistance is increased in the size of the current?
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
A circuit has total resistance of 5 ohms and a current of 0.3 amperes What voltage must the battery supply?
1.5 volts
What is the total resistance of three resistors in parallel with values of 2 ohms 8 ohms and 14 ohms?
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
A cell of emf 3.0 volts and internal resistance of 0.01 ohm is connected through an ammeter of 0.05-ohm internal resistance to a 5.0 rheostat by wire having a total resistance of 0.85-ohm?
total voltage = 4.5V, total resistance = 3.5 ohms, loop current = 4.5V / 3.5 ohms = 1.286Atotal voltage = 9V, total resistance = 4 ohms, loop current = 9V / 4 ohms = 2.25Atotal voltage = 13.5V, total resistance = 4.5 ohms, loop current = 13.5V / 4.5 ohms = 3Aetc.There is no solution to your problem conditions.
If three cells that each have an emf 1.5 volts and an internal resistance of 2 ohms are connected in series to a resistor of 44 ohms what is the current through the resistor?
Taking the question at face value, the internal resistances will be treated like "real" resistors in the circuit. That means we have 3 batteries of 1.5 volts each connected in series with their 2 ohms + 2 ohms + 2 ohms of internal risistance, or 6 ohms of internal resistance. The 6 ohms of internal resistance acts in series with the 44 ohms of resistance stated as the value of the resistor. The total resistance is simply the sum of the two, or 6 ohms + 44 ohms or 50 ohms of total resistance. The batteries are connected in series, and their individual voltages are added to find total applied voltage. That means 1.5 volts + 1.5 volts + 1.5 volts or 4.5 volts will be the total applied voltage. Total current in the circuit (and through our 44 ohm resistor) will be the voltage applied divided by the resistance ( I = E / R), which, in this case, is 4.5 volts / 50 ohms which equals 0.07 amps. That's 7/100ths of an amp, or, in electronics speak, 70/1000ths of an amp, or 70 milliamps, or 70mA of current. The circuit is a series circuit, and that current, the total circuit current, will be flowing through each and every component of the circuit. That's what a series circuit means.
What is the current in a parallel circuit which has two resistors (17.2 ohms and 22.4 ohms) and a power source of 6.0 volts?
By Ohm's Law, current is voltage divided by resistance, so a voltage of 6 volts across a resistance of 24 ohms will develop a current of 0.25 amperes.
What is the current for 20 volts and 2 ohms?
1 amp.
A 240 volt single phase circuit has a resistive load of 8500 what is the net calculated current to supply this load?
Ohm's law: Volts = Amps * Ohms, or Amps = Volts / Ohms 240 volts / 8500 ohms = 28 milliamps
