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Cu2S + O2 ---> Cu2O + SO2

On the left hand side we count up all the individual atoms:

Cu = 2

S = 1

O = 2

On the right hand side we do the same:

Cu = 2

S = 1

O = 3

Notice we have one extra O atom on the right? To fix that we would have to have 11/2 O2 on the left hand side.

Cu2S + 11/2O2 ---> Cu2O + SO2

Because you can't use fractions when balancing equations, we double the whole equation, resulting in a balanced equation with no fractions.

2Cu2S + 3O2 ---> 2Cu2O + 2SO2

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13y ago
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Wiki User

12y ago

First, the category you chose for this question is way off...but ill answer it. i believe its Cu2O plus C yields Cu2 plus CO.

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14y ago

2Cu + O2 -> 2Cu2O

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10y ago

2Cu2S + 3O2 --> 2Cu2O + 2SO2

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Q: What is this equation correctly balanced Cu2S O2 Cu2O SO2?
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