iron being highly electropositive it does not react with covalent compound formed by two electropositive elements. that is tin nitride.
No, because tin is above lead in the activity series.
It isn't used for anything. It turns out that tin nitrate (also "stannous nitrate" - the Latin word for tin is Stannum, hence the chemical symbol Sn) is a very unstable high explosive. If you rub it strongly, strike it with a hammer or heat it above 100 degrees C, it blows up.
BeI2(aq) + Sn(NO3)2(aq) => Be(NO3)2(aq) + SnI2(aq)
Silver is slightly more reactive than gold, although they are both very unreactive. Assuming that the gold nitrate exists, because it would be very rare, silver would react with it and displace it. The products formed will be silver nitrate and gold.
The tin ion, Sn2+, and the nitrate ion, NO3-.
iron being highly electropositive it does not react with covalent compound formed by two electropositive elements. that is tin nitride.
The reaction will be Tin Nitrate and Hydrogen Gas.
No, because tin is above lead in the activity series.
It isn't used for anything. It turns out that tin nitrate (also "stannous nitrate" - the Latin word for tin is Stannum, hence the chemical symbol Sn) is a very unstable high explosive. If you rub it strongly, strike it with a hammer or heat it above 100 degrees C, it blows up.
Bronze is an alloy that consists of copper and usually tin. When added to nitric acid, the nitrate anions attack the tin and copper cations to produce copper (II) nitrate and Tin (II) nitrate. Nitrogen monoxide is released but reacts with oxygen in the air to produce nitrogen dioxide.
15.451
Yes I did it in lab yesterday.
previous answer-> "tin(II)nitride --> SnN" what?? I'm pretty sure it's Sn3N2 Nitrogen (nitride) has -3 charge
Silver nitrate have colourless crystals if it is pure.
Formulas are: Sn(NO3)2 and Sn(NO3)4.
BeI2(aq) + Sn(NO3)2(aq) => Be(NO3)2(aq) + SnI2(aq)